Answer:
To fulfill octet of B atom in borane, nucleophilic attack by pi electrons of alkene takes place with electrophilic B center in borane.
Explanation:
In Borane (), B atom has energetically vacant 2p orbital and thereby octet is incomplete.Therefore B center in borane act as an electrophilic center.
In alkene, pi bonding electrons are loosely bound together due to side on overlap of two constituent p-orbitals. Hence this pi bond can be easily broken. Alternatively, we can say that pi bond in alkene act as a potential nucleophile.
The first step of hydroboration occurs in a concerted manner where pi electrons of alkene first attack vacant 2p orbital of B in borane to fulfill it's octet (represented by an arrow drawn from alkene to B atom) and forms a 4 memebered cyclic intermediate. Simulaneously, a B-H bond in borane is donated to alkene through 3c-2e bond (3 center-2 electron bond).
Full mechanism has been shown below.
Answer:
<h3>The answer is option D</h3>
Explanation:
To find the speed given the kinetic energy and mass we use the formula
where
m is the mass
v is the speed
From the question
KE = 15 J
m = 2.3 kg
We have
We have the final answer as
<h3>3.6 m/s</h3>
Hope this helps you
Given :
Molarity of , M = 0.213 M .
To Find :
How many ml of 0.213 M of are required to deliver 66.4 mmol .
Solution :
Volume required :
So ,
Therefore , volume of required is 103.91 ml .
Hence , this is the required solution .
Mg is ahead of Al in the electrochemical series and more reactive than Al hence Al does not react with MgCl2.
A chemical reaction is said to have occurred when new substances are formed. The reaction between magnesium chloride solution and sodium carbonate solution is a double decomposition reaction since the cations exchange anion partners in the product;
MgCl2(aq) + Na2CO3(aq) ------> MgCO3(s) + 2NaCl(aq)
We must note that a single replacement reaction depends on the relative positions of metals in the electrochemical series. Al can react with CuCl2 because Al is more reactive than copper and ahead of Cu in the electrochemical series. On the other hand, Mg is ahead of Al in the electrochemical series and more reactive than Al hence Al does not react with MgCl2.
Lear more about electrochemical series: brainly.com/question/25749323
Yes, It is important to know the volume of Unknown acid or base to be titrated.
Titration is carried out in order to find out the concentration (i.e. molarity) of unknown acid or base. In this process a standard solution of acid or base is taken and is titrated with known volume of of titrant. At end point (neutralization) the amount of standard titrant utilized is calculated and following formula is employed to calculate the unknown concentration of unknown solution.
M₁V₁/n₁ = M₂V₂/n₂