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Phoenix [80]
2 years ago
12

I need help with this

Mathematics
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

the earth because

Step-by-step explanation:

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Approximate the change in the volume of a right circular cylinder of fixed radius requals21 cm when its height decreases from he
Tasya [4]
The volume of the cylinder is given by:
 V = pi * r ^ 2 * h
 For h = 12cm:
 V1 = pi * ((21) ^ 2) * (12)
 V1 = 16625.30832 cm ^ 3
 For h = 11.9cm:
 V2 = pi * ((21) ^ 2) * (11.9)
 V2 = 16486.76409 cm ^ 3
 The change in volume is given by:
 V1-V2 = 16625.30832-16486.76409
 V1-V2 = 138.54423 cm ^ 3
 Answer:
 the change in the volume is:
 V1-V2 = 138.54423 cm ^ 3
4 0
3 years ago
Are these correct? If not please help me write the correct answer.​
Keith_Richards [23]

Answer:

Mostly correct

For Q3, you are doing great, you remembered that negative numbers can happen if the exponent is an odd number.

For Q4, I think you were confused with the fractions,

4(i)

(\frac{2}{3} )^{4} = (\frac{2^{4}}{3^{4}}) = (\frac{16}{81}) =0.198

4(ii) is also wrong but I'll let you try to fix it yourself following what I given you for 4(i). You should get 1/64

Hope this helps!

4 0
3 years ago
Read 2 more answers
For what value(s) of k is the linear system consistent? (Enter your answers as a comma-separated list.)
AleksAgata [21]

Answer:

Step-by-step explanation:

Given

6x_1-9x_2=8

9x_1+kx_2=-1

The given system is AX=B can be represented by

\begin{bmatrix}6 &-9 \\ 9 & k\end{bmatrix}\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}8\\ -1\end{bmatrix}

The given system is consistent when determinant of A is not equal to zero

|A|

|A|=6k-(-81)=6k+81

k\neq \frac{-27}{2}

i.e. system is consistent for all value of k except k=\frac{-27}{2}

R-\frac{-27}{2}

                 

4 0
3 years ago
Read 2 more answers
1-(-4) ,, (-4) is squared outside the parentheses
Naddika [18.5K]
1-(-4)^2
1-(-4 times -4)
1-(16)
1-16
-15
5 0
3 years ago
What is 823,563 rounded to the nearest ten thousand? (1 poin<br> 820.000<br> 325.000<br> 330.000
valentina_108 [34]

Answer: 820,000

823,563 rounded to the nearest ten thousand is 820,000

3 0
3 years ago
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