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3 years ago

If a magnet can cut into a small piece , each piece will remain a magnet ? Explain this phenomenon

Physics

1 answer:

Hitman42 [59]3 years ago

8 0

yes ,each piece will remain a magnet because the small pieces will cut into north and south

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A particle of mass 4.0 kg is constrained to move along the x-axis under a single force F(x) = −cx3 , where c = 8.0 N/m3 . The pa

Pie

Answer:4.58 m/s

Explanation:

Given

mass of Particle $m=4 kg$

$F=-cx^3$

$a=\frac{F}{m}$

$a=-\frac{cx^3}{m}$

$a=-\frac{8x^3}{4}$

$a=-2x^3$

$v\frac{\mathrm{d} v}{\mathrm{d} x}=-2x^3$

$vdv=-2x^3dx$

integrating

$\int_{6}^{v_b}vdv=\int_{1}^{-2}-2x^3dx$

$\frac{v_b^2-6^2}{2}=-\frac{1}{2}\left [ \left ( -2\right )^4-\left ( 1\right )^4\right ]$

$\frac{v_b^2-36}{2}=-0.5\times 15$

$v_b^2=36-15$

$v_b=\sqrt{21}$

$v_b=4.58 m/s$

6 0

3 years ago

Why is moon is non-lomis back

qwelly [4]

Explanation:

At night, when that part of Earth is facing away from the sun, space looks black because there 8s no nearby bright source of light like the sun , to be scattered

4 0

4 years ago

A cylindrically shaped piece of collagen (a substance found in the body in connective tissue) is being stretched by a force that

Marat540 [252]

Answer:

Part(a): The value of the spring constant is $3.11 \times 10^{2}~Kg~s^{-2}$ .

Part(b): The work done by the variable force that stretches the collagen is $1.5 \times 10^{-6}~J$ .

Explanation:

Part(a):

If ' $k$ ' be the force constant and if due the application of a force ' $F$ ' on the collagen ' $\Delta l$ ' be it's increase in length, then from Hook's law

$F = k~\Delta l....................................................................(I)$

Also, Young's modulus of a material is given by

$Y = \dfrac{F/A}{\Delta l/l}...............................................................(II)$

where ' $A$ ' is the area of the material and ' $l$ ' is the length.

Comparing equation ( $I$ ) and ( $II$ ) we can write

$&& Y = \dfrac{l~k}{A}\\&or,& k = \dfrac{Y~A}{l}\\&or,& k = \dfrac{Y~(\pi~r^{2})}{l}$

Here, we have to consider only the circular surface of the collagen as force is applied only perpendicular to this surface.

Substituting the given values in equation ( $III$ ), we have

$k = \dfrac{3.10 \times 10^{6}~N~m^{-2} \times \pi \times (0.00093)^{2}~m^{2}}{.027~m} = 3.11 \times 10^{2}~Kg~s^{-2}$

Part(b):

We know the amount of work done ( $W$ ) on the collagen is stored as a potential energy ( $U$ ) within it. Now, the amount of work done by the variable force that stretches the collagen can be written as

$W = \dfrac{1}{2}k~x^{2} = \dfrac{(\dfrac{F}{k})^{2}k}{2} = \dfrac{F^{2}}{2~k}...................................(IV)$

Substituting all the values, we can write

$W = \dfrac{(3.06 \times 10^{-2})^{2}~N^{2}}{2 \times 3.11 \times 10^{2}~Kg~s^{-2}} = 1.5 \times 10^{-6}~J$

3 0

3 years ago

How do the positions of the hot and cold water affect the speed of convection

Aleks [24]

Convection is the process in which heat is transferred by movement of a heated fluid such as air or water. Natural convection results from the tendency of most fluids to expand when heated so it becomes less dense and rise above.

For example- In a pot of water on a stove the liquid t bottom is heated by conduction. The hot water has lower density and it rises above pushing the cold water downwards so it gets heated.

5 0

3 years ago

Read 2 more answers

I NEED THIS ASAP<br> What does the satellite image below represent?

motikmotik

It might be a low pressure

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3 years ago