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Sergeeva-Olga [200]
3 years ago
7

If a magnet can cut into a small piece , each piece will remain a magnet ? Explain this phenomenon

Physics
1 answer:
Hitman42 [59]3 years ago
8 0

yes ,each piece will remain a magnet because the small pieces will cut into north and south

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PLEASE HURRY What is "a section of a chromosome that typically contains the code for a particular protein, which determines a sp
castortr0y [4]

Answer:

It is a gene!!

Explanation:

It is because RNA is referred to as a gene. Genes are contained in chromosones.

6 0
3 years ago
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.00 m, rotating in such a way that it makes one revolution in 2
Vaselesa [24]

Answer:

2.01

Explanation:

First, we need to find the centripetal acceleration.

We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute

Now this speed gotten in rpm will be converted to m/s, to ease the calculation

30 rpm = πdN/60 m/s

30 rpm = (3.142 * 4 * 30)/60

30 rpm = 377.04/60

30 rpm = 6.284 m/s

a(c) = v²/r

a(c) = 6.284²/2

a(c) = 39.49 / 2

a(c) = 19.74 m/s²

F = ma

F = 50 * 19.74

F = 987 N

Also, Normal Force, F(n) =

F(n) = mg

F(n) = 50 * 9.81

F(n) = 490.5

We then use this to find the coefficient of static friction, μ

μ = F/F(n)

μ = 987 / 490.5

μ = 2.01

7 0
3 years ago
Newton’s 3rd law is for every action, there is an equal and opposite reaction <br><br> True of false
den301095 [7]

Answer:

true

Explanation:

newton's third law of motion states that if body A exerts a force on the body B, then body B will exert an equal and opposite force on body A,

this is called action reaction pair

hope this helps

8 0
3 years ago
What is the unit measurement for force
Vaselesa [24]

The SI / Metric unit of force is the ' Newton '.

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6 0
4 years ago
Read 2 more answers
A very long uniform line of charge has charge per unit length 4.54 μC/m and lies along the x-axis. A second long uniform line of
kozerog [31]

Answer:

The magnitude of the net electric field is 6.57\times10^{5}\ N/C

Explanation:

Given that,

Charge density \lambda = 4.54\ \mu C/m

Charge density \lambda' = -2.58\ \mu C/m

Distance y_{1}= 0.384\ m

Distance y_{2}= 0.204\ m

We need to calculate the magnitude of the net electric field

Using formula of electric field

E=E_{1}+E_{2}

E=\dfrac{1}{2\pi\epsilon_{0}}(\dfrac{\lambda}{r}+\dfrac{\lambda'}{r'})

Put the value into the formula

E=\dfrac{1}{2\pi\times8.85\times10^{-12}}(\dfrac{4.54\times10^{-6}}{0.204}+\dfrac{2.58\times10^{-6}}{0.384-0.204})

E=6.57\times10^{5}\ N/C

Hence, The magnitude of the net electric field is 6.57\times10^{5}\ N/C

8 0
4 years ago
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