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alexandr402 [8]
3 years ago
7

The force that directly propels a motor scooter along a highway is that provided by the

Physics
1 answer:
denis23 [38]3 years ago
5 0
It’s the tires because there the only thing directly moving it
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Show your work and resoning for the below requirement.
Leno4ka [110]

Answer:

This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap

Explanation:

We must work on this problem using the rotational equilibrium equations and then they compared the tension values that the cable supports.

Let's start with fixing a reference system on the hinge of the flag, we take as positive the anti-clockwise turn

 They indicate the weight of the pole W₁ = 120 lb and a length of L = 9 ft, the weight of the man W₂ = 150, we assume that the cable is at the tip of the pole

            - T_{y} L + W₂ L + W₁ L / 2 = 0

            T_{y} = W₂ + W₁ / 2

            T_{y} = 120 + 150/2

            T_{y} = 195 lb

we use trigonometry to find the cable tension

             sin 30 = T_{y} / T

             T = T_{y} / sin 30

             T = 195 / sin 30

             T = 390 lb

This value is less than the maximum tension of 500 lbs, making it safe for man to go to the tip flap

             T < 500 lb

4 0
4 years ago
In a mixture, the ingredients intermingle and
nirvana33 [79]
They do not react with or chemically bond to each other.
7 0
3 years ago
A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 33.0°. It momentarily stops when it has rolled 1.7
galben [10]

Answer:

v = 3.6 m/s

Explanation:

given,

Inclination of the ramp, θ = 33⁰

Distance of the rope, d = 1.70 m

initial speed = ?

using conservation of energy

\dfrac{1}{2}mv^2 + \dfrac{1}{2}I_{com}\omega^2 = m g h

h = d sinθ  

h = 1.7 x sin 33° = 0.926 m

moment of inertia of the solid ball

I_{com}= \dfrac{2}{5}MR^2  

we know, v = r ω

\dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{2}{5}mR^2\times \dfrac{v^2}{R^2}= m g h

\dfrac{1}{2}mv^2 + \dfrac{1}{5}mv^2 = mgh

gh= \dfrac{7}{10}v^2

v = \sqrt{\dfrac{10}{7}gh}

v = \sqrt{\dfrac{10}{7}\times 9.8\times 0.926}

v = 3.6 m/s

Hence, initial speed of the solid ball = 3.6 m/s

8 0
3 years ago
True or false?<br> There is no<br> difference<br> between speed<br> and velocity
lukranit [14]

Answer:

False

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement.

3 0
3 years ago
What is the frequency of a wave with a velocity of 21.2 m/s and a wavelength of 8.3m?
Margaret [11]

Answer:

2.55 Hz

Explanation:

frequency = Speed of wave / wavelength

= 21.2 / 8.3

= 2.55 Hz

3 0
3 years ago
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