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katrin [286]
3 years ago
12

Lines n and m are parallel and lines s and t are parallel, as shown.

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0

Answer:

60

Step-by-step explanation:

straight lines are 180

since all lines are parallel

180 - 120 = 60

liubo4ka [24]3 years ago
5 0

Answer:

the answer is 60

Step-by-step explanation:

it is the answer

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At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion ring
andre [41]

Answer:

The number of onion rings is <u>3</u> in the combination meal and the number of sliders is <u>2</u> in the combination meal.

Step-by-step explanation:

Given:

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion rings and sliders has a total of 5 onion rings and sliders altogether and contains 695 calories.

Now, to find the number of onion rings in the combination meal and the number of sliders in the combination meal.

Let the number of onion rings in the combination meal be x.

And let the number of sliders in the combination meal be y.

<u><em>So, the total number of onion rings and sliders are:</em></u>

x+y=5\\\\y=5-x\ \ \ .....(1)

Now, the total number of calories each onion rings and sliders has:

x(65)+y(250)=695

Substituting the value of y from equation (1) we get:

<em />x(65)+(5-x)(250)=695\\\\65x+1250-250x=695\\\\1250-185x=695<em />

<em>Subtracting both sides by 1250 we get:</em>

<em />-185x=-555<em />

<em>Dividing both sides by -185 we get:</em>

x=3.

<u><em>The number of onion rings in the combination meal = 3.</em></u>

Now, substituting the value of x in equation (1) we get:

y=5-x\\\\y=5-3\\\\y=2.

<u><em>The number of sliders in the combination meal = 2.</em></u>

Hence, the number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)
SashulF [63]

\implies {\blue {\boxed {\boxed {\purple {\sf {   \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 {x}^{2}  +  4x + 6)(7x + 5)

= \: 7x(4 {x}^{2}  + 4x + 6) + 5(4 {x}^{2}  + 4x + 6)

=  \: 28 {x}^{3}  + 28 {x}^{2}  + 42x + 20 {x}^{2}  + 20x + 30

Combining like terms, we have

=  \: 28 {x}^{3}  + (28 {x}^{2}  + 20 {x}^{2} ) + (42x + 20x) + 30

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\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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