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3 years ago

Calculate the volume of 0.250 M H2SO4 that contains 0.00255 mol H2SO4.

Chemistry

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

0.0102 L or 10.2 mL

Explanation:

From the question given above, the following data were obtained:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume as follow:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity = mole / Volume

0.250 = 0.00255 / volume

Cross multiply

0.250 × volume = 0.00255

Divide both side by 0.250

Volume = 0.00255 / 0.250

Volume = 0.0102 L

Covert 0.0102 L to mL.

1 L = 1000 mL

Therefore,

0.0102 L = 0.0102 L × 1000 / 1 L

0.0102 L = 10.2 mL

Thus, the volume is 0.0102 L or 10.2 mL

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3 years ago

25.2 mL of water are placed in a graduated cylinder. A 22.6 g stone is dropped in, and the water level rises to 32.4 mL. Find th

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3 years ago

4 Elliot has some stearic acid. It is in the solid state.

Ahat [919]

Answer:

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Explanation:

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3 years ago

An acid solution is 0.100 M in HCl and 0.210 M in H2SO4. What volume of a 0.150 M solution of KOH must be added to 500.0 mL of t

Dmitry_Shevchenko [17]

Answer:

When we add 0.33L of KOH only the HCl solution will be neutralized. When we add 1.4 L of KOH, all of the acid (the HCl and H2SO4 solution) will be neutralized.

Explanation:

Step 1: Data given

The solution has 0.100 M HCl and 0.210 M H2SO4

Molarity KOH = 0.150 M

Volume of acid solution = 500 mL = 0.5 L

Step 2: Calculate moles of HCl

Moles HCl = Molarity HCl * volume

Moles HCl = 0.100 M * 0.5 L

Moles HCl = 0.05 moles

Step 3: Calculate moles of H2SO4

Moles H2SO4 = 0.210 M * 0.5 L

Moles H2SO4 = 0.105 moles

Step 4: The balanced neutralization reaction of KOH with HCl can be written as:

KOH + HCl → KCl + H2O

The mole ratio is 1:1

This means to neutralize 0.05 moles HCl, we need 0.05 moles KOH

Step 5: The balanced neutralization reaction of KOH with H2SO4 can be written as:

2KOH + H2SO4 → K2SO4 + 2H2O

The mole ratio KOH: H2SO4 is 2:1

This means to neutralize 0.105 moles H2SO4 we need 0.210 moles KOH

Step 6: Calculate volume of KOH needed to neutralize the solution

To neutralize the HCl solution: 0.05 moles / 0.150 M = 0.33 L KOH needed

To neutralize the H2SO4 solution: 0.210 moles / 0.150 M = 1.4 L KOH needed

When we add 0.33L of KOH the HCl solution will be neutralized. When we add 1.4 L of KOH the HCl and H2SO4 solution will be neutralized.

4 0

3 years ago

Medical cold packs can use various chemicals in order to produce a cold compress to help reduce inflammation caused by injuries.

Illusion [34]

Answer:

Mass of KCL = 218 grams.

Explanation:

Step 1: calculate the heat that must be absorbed(q).

Heat that must be absorbed(q) is calculated as follows:

q= m c (T2-T1).

q = 750g (4.18 J/gC)(20-4 C) = 5.016X10^4 J = 50.16 kJ

Step 2: we determine moles of KCL as follows:

Moles KCl = 50.16 kJ / 17.2 kJ/mol = 2.92 moles.

Step 3: calculate mass of KCL:

Mass of KCl = 2.92 mol X 74.55 g/mol = 218g.

Therefore, 218 grams of KCL would have to be dissolved into 750 g of 20.0°C H2O to produce the solution.

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3 years ago

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