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LiRa [457]
2 years ago
8

Calculate the volume of 0.250 M H2SO4 that contains 0.00255 mol H2SO4.

Chemistry
1 answer:
antoniya [11.8K]2 years ago
4 0

Answer:

0.0102 L or 10.2 mL

Explanation:

From the question given above, the following data were obtained:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume as follow:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity = mole / Volume

0.250 = 0.00255 / volume

Cross multiply

0.250 × volume = 0.00255

Divide both side by 0.250

Volume = 0.00255 / 0.250

Volume = 0.0102 L

Covert 0.0102 L to mL.

1 L = 1000 mL

Therefore,

0.0102 L = 0.0102 L × 1000 / 1 L

0.0102 L = 10.2 mL

Thus, the volume is 0.0102 L or 10.2 mL

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A certain substance X has a normal freezing point of −3.1°C and a molal freezing point depression constant =Kf·6.23°C·kgmol−1. C
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Answer:

Freezing T° of solution =  - 7.35 °C

Explanation:

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