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3 years ago

Calculate the volume of 0.250 M H2SO4 that contains 0.00255 mol H2SO4.

Chemistry

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

0.0102 L or 10.2 mL

Explanation:

From the question given above, the following data were obtained:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume as follow:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity = mole / Volume

0.250 = 0.00255 / volume

Cross multiply

0.250 × volume = 0.00255

Divide both side by 0.250

Volume = 0.00255 / 0.250

Volume = 0.0102 L

Covert 0.0102 L to mL.

1 L = 1000 mL

Therefore,

0.0102 L = 0.0102 L × 1000 / 1 L

0.0102 L = 10.2 mL

Thus, the volume is 0.0102 L or 10.2 mL

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3 years ago

Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol$

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

$P'V'=n'RT'$

$n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol$

$CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)$

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

$\frac{3}{1}\times 0.6402 mol=1.9208 mol$ of hydrogen gas

Moles of hydrogen gas obtained theoretically = 1.9208 mol

The reaction produces 26.0 L of hydrogen gas measured at STP.

At STP, 1 mole of gas occupies 22.4 L of volume.

Then 26 L of volume of gas will be occupied by:

$\frac{1}{22.4 L}\times 26 L= 1.1607 mol$

Moles of hydrogen gas obtained experimentally = 1.1607 mol

Percentage yield of hydrogen gas of the reaction:

$\frac{Experimental}{Theoretical}\times 100$

$\%=\frac{ 1.1607 mol}{1.9208 mol}\times 100=60.42\%$

60.42% is the percent yield of the reaction.

8 0

3 years ago

Please help as soon and best answer gets brainlest

Ann [662]

Answer:

Mass, temperature, and phase.

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2 years ago

If a recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb what volume in liters

Bad White [126]

The volume in liters of 3245 aluminum cans is 24.8 L.

A recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb. The mass of 3245 aluminum cans is:

$3245 cans \times \frac{1lb}{22cans} = 147.5 lb$

To convert mass to volume, we need the density of aluminum (5.95 lb/L). The volume corresponding to 147.5 lb of aluminum is:

$147.5 lb \times \frac{1L}{5.95 lb} = 24.8 L$

The volume in liters of 3245 aluminum cans is 24.8 L.

You can learn more about density here: brainly.com/question/1841285

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3 years ago

Increasing the temperature of the solvent ____________________ the solubility of a solid solute and _______________________ the

Marina86 [1]

Answer:

increase in solvent temperature will increase the solubility of solid particle but decreases the solubility of gas particle.

Explanation:

In solid particle when temperature increases its help to break apart the solid particle and increase in kinetic energy of solvent results in increase in solubility of solid particles in solvent.

but in gas solute, increase in temperature of solvent causes the increase in motion of gas molecules means increase in kinetic energy of molecules in the gas which results in breakage of inter molecular bonds and removal of the molecules from the heated solution.

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3 years ago