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Anastaziya [24]
3 years ago
5

What is the number of moles of potassium chloride present in 148 g of kcl?

Chemistry
2 answers:
OLga [1]3 years ago
3 0
The number of moles of one substance given the amount in mass can be calculated by the use of the molar mass. This is the mass of a compound per 1 mol of the said substance. For, KCl the molar mass is 74.55 g/ mol

148 g / 74.55 g/mol = 2 mol KCl

Hope this answers the question. have a nice day.
lisov135 [29]3 years ago
3 0

Answer : The number of moles of potassium chloride is, 1.99 moles.

Explanation : Given,

Mass of KCl = 148 g

Molar mass of KCl = 74.5 g/mol

Formula used :

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}

Now put all the given values in this formula, we get the moles of KCl.

\text{Moles of }KCl=\frac{148g}{74.5g/mol}=1.99mole

Therefore, the number of moles of potassium chloride is, 1.99 moles.

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A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
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Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

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q = heat released by the reaction

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c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

\Delta T = change in temperature = T_2-T_1=(23.73-26.01)=-2.28^oC

Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

q=-4208.28J=-4.81kJ

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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