All categories

3 years ago

What is the number of moles of potassium chloride present in 148 g of kcl?

2 answers:

3 0

The number of moles of one substance given the amount in mass can be calculated by the use of the molar mass. This is the mass of a compound per 1 mol of the said substance. For, KCl the molar mass is 74.55 g/ mol

148 g / 74.55 g/mol = 2 mol KCl

Hope this answers the question. have a nice day.

lisov135 [29]3 years ago

3 0

Answer : The number of moles of potassium chloride is, 1.99 moles.

Explanation : Given,

Mass of KCl = 148 g

Molar mass of KCl = 74.5 g/mol

Formula used :

$\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}$

Now put all the given values in this formula, we get the moles of KCl.

$\text{Moles of }KCl=\frac{148g}{74.5g/mol}=1.99mole$

Therefore, the number of moles of potassium chloride is, 1.99 moles.

You might be interested in

Electrons orbit the nucleus in specified energy

pashok25 [27]

Answer:

because the electron is a negatively charge and have high energy

5 0

3 years ago

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

4 0

3 years ago

If mixture didn't exist how would life be different PLEASEEE QUICKKKK

Nataliya [291]

Answer:

boring

Explanation:

without meaning

8 0

3 years ago

In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is

Vera_Pavlovna [14]

6.02x10^23 atoms is the answer

8 0

3 years ago

How many moles of liquid water must freeze to remove 100 kJ of heat? (ΔHf = –334 J/ g.

Juliette [100K]

First figure out how many grams must freeze and then convert the grams to moles.
Hf = -334 J/g. Convert this to KJ/g by dividing by 1000. (There are 1000 Joules in a kJ). 
Hf = -334 J/g ÷ 1000 J/kj = -0.334 kJ/g 
Now, divide 100 kJ by -0.334 kJ/g (see how the units are lining up?) 
100 kJ ÷ -0.334 kJ/g = 299 g 
Now convert this to moles by dividing by the molecular weight of water (18.0g/mole). 
299 ÷ 18.0 = 16.6 moles

5 0

3 years ago