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3 years ago

How are mass and volume alike?

Physics

1 answer:

balu736 [363]3 years ago

6 0

THE ANSWER IS B THE CEASE TO EXIST WHEN LAVED IN LIQUDI hope that helped

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Receiving delicious food is to escaping electric shock as ________ is to ________.

Aleks [24]

Answer:

positive reinforcer; negative reinforcer

Explanation:

positive reinforcer; negative reinforcer

Receiving delicious food can be seen as a positive reinforcer while escaping electric shock can be seen as a negative reinforcer.

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3 years ago

What molecule(s) does carbon, hydrogen, and oxygen come from?

Hunter-Best [27]

The molecule they all come from is water molecule

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3 years ago

s person is deciding whether to install solar panels on her house. lt and explain three pieces of info she needs to consider to

Marrrta [24]

Efficiency- How much energy is wasted and how much useful energy is produced
Money- How expensive to install them
Location- She has to consider the location where she places them so that there is enough sunlight and light energy for the solar panels, obviously she should have solar panels if the location receives a sufficient amount of sunlight

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4 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$

Generelly

$KE_b = \frac{1}{2} m v^2$

And $PE_b = q V_a$

Equating this two formulas

$\frac{1}{2} mv^2 = q V_a$

making v the subject

$v = \sqrt{\frac{q V_a}{2 m} }$

Substituting value

$v = \sqrt{\frac{ 2* 1.602 *10^{-19} * 1.8 *10^{3}}{2 * 6.64 *10^{-27}} }$

$v = 41.65*10^4 m/s$

Generally the electric field between the plates is mathematically represented as

$E = \frac{V_b}{d}$

Substituting value

$E = \frac{120}{8*10^{-3}}$

$E = 15 *10^3 NC^{-1}$

the magnetic field is mathematically evaluate

$B = \frac{E}{v}$

$B = \frac{15 *10^{3}}{41.65 *10^4}$

$B = 0.0036T$

6 0

3 years ago

A historical society is testing an old cannon. They

sveta [45]

Answer:

26.2 m/s

Explanation:

We can find the speed of the cannonball just by analyzing its vertical motion. In fact, the initial vertical velocity is

$u_y = u sin \theta$ (1)

where u is the initial speed and $\theta = 45.0^{\circ}$ is the angle of projection.

We can therefore use the following suvat equation for the vertical motion of the ball:

$v_y = u_y + at$

where $v_y$ is the vertical velocity at time t, and $a=g=-9.8 m/s^2$ is the acceleration of gravity. The time of flight is 3.78 s, so we know that the ball reaches its maximum height at half this time: