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alexdok [17]
3 years ago
12

How are mass and volume alike?

Physics
1 answer:
balu736 [363]3 years ago
6 0
THE ANSWER IS B THE CEASE TO EXIST WHEN LAVED IN LIQUDI hope that helped
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A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between
Oduvanchick [21]

Answer:

Net electric field, E_{net}=91406.24\ N/C

Explanation:

Given that,

Charge 1, q_1=7.5\ nC=7.5\times 10^{-9}\ C

Charge 2, q_2=-2.9\ nC=-2.9\times 10^{-9}\ C

distance, d = 3.2 cm = 0.032 m

Electric field due to charge 1 is given by :

E_1=\dfrac{kq_1}{r^2}

E_1=\dfrac{9\times 10^9\times 7.5\times 10^{-9}}{(0.032)^2}

E_1=65917.96\ N/C

Electric field due to charge 2 is given by :

E_2=\dfrac{kq_2}{r^2}

E_2=\dfrac{9\times 10^9\times 2.9\times 10^{-9}}{(0.032)^2}

E_2=25488.28\ N/C

The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :

E_{net}=E_1+E_2

E_{net}=65917.96+25488.28

E_{net}=91406.24\ N/C

So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.

3 0
4 years ago
A bucket of warm water can be considered a closed system for a very short period of time. Which best explains this phenomenon? A
zlopas [31]
The reason is that a closed system has nothing going in or out and water retains energy very well also water it polar so it is attracted to itself. It doesnt like contact with other things.
So it's likely to be C
3 0
3 years ago
What is the colour of a shirt which has blue and white stripes when put under yellow light? Explain.​
GenaCL600 [577]

Answer:

Black and yellow strips.

Explanation:

Color of shirt is blue and white stripes

When the shirt is seen in the yellow light, the blue color do not reflect any color so it appears black and the white color reflects the yellow light so it appears yellow.

Thus, the color of shirt is blue appears black and white appears yellow.

8 0
3 years ago
8. How many calories of heat energy (Q) would be released as a 2,500 g iron (Fe) frying pan at 190˚C cools to 25˚C?
Sedaia [141]

Answer:

Q=197505J

Explanation:

From the question we are told that:

Mass m=2500g=2.5kg

Initial heat of pan i_h=190 \tetxtdegree

Final heat of pan f_h=25˚C \tetxtdegree

 

Generally the equation for Heat energy released is mathematically given by

 Q=mC \triangle T\\\\Q=2.5*462 *(190-26)\\\\Q=1155 *(190-26)\\\\Q=1155 *(171)\\

 Q=197505J

3 0
3 years ago
) Calculate current passing in an electrical circuit if you know that the voltage is 8 volts and the resistance is 10 ohms
Svetach [21]

Explanation:

<em>Hey</em><em>,</em><em> </em><em>there</em><em>!</em>

<em>Here</em><em>,</em><em> </em><em>In</em><em> </em><em>question</em><em> </em><em>given</em><em> </em><em>that</em><em>, </em>

<em>potential</em><em> </em><em>difference</em><em> </em><em>(</em><em>V</em><em>)</em><em>=</em><em> </em><em>8</em><em>V</em>

<em>resistance</em><em> </em><em>(</em><em>R</em><em>)</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ohm</em>

<em>Now</em><em>,</em>

<em>According</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Ohm's</em><em> </em><em>law</em><em>,</em>

<em>V</em><em>=</em><em> </em><em>R</em><em>×</em><em>I</em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>where</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>current</em><em>}</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>V</em><em>/</em><em>R</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>8</em><em>/</em><em>1</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>current</em><em> </em><em>is</em><em> </em><em>4</em><em>/</em><em>5</em><em> </em><em>A</em><em> </em><em>or</em><em> </em><em>0</em><em>.</em><em>8</em><em> </em><em>A</em><em>.</em>

<em>(</em><em>A</em><em>=</em><em> </em><em>ampere</em><em> </em><em>=</em><em> </em><em>unit</em><em> </em><em>of</em><em> </em><em>current</em><em>)</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em> </em>

6 0
4 years ago
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