Answer:
2 x 10^14 N/Cs
Explanation:
radius, r = 3 cm
Area , A = 3.14 x 3 x 3 = 28.26 cm^2 = 28.26 x 10^-4 m^2
d = 1.1 mm = 1.1 x 10^-3 m
i = 5 A
Let time be t and electric field strength is E.
Charge, q = i x t = 5 t
q = C V
q = C x E x d
E/t = 2 x 10^14 N/Cs
<h2>Answer:</h2><h2>The depth of barge float=
3 cm</h2><h2>
Explanation:</h2>
Length of rectangular barge=5.2 m
Width of rectangular barge=2.4m
Mass of crate=410 kg
Let h be the height of barge float
Volume of barge float=
Density of water=
Weight of water displaced by barge=Buoyant force=-Weight of horse
1 m=100 cm
cm
Hence, the depth of barge float=3 cm
<h2 />
<span>Glycolysis. In glycolysis, glucose—a six-carbon sugar—undergoes a series of chemical transformations. In the end, it gets converted into two molecules of pyruvate, a three-carbon organic molecule.
Pyruvate oxidation. Each pyruvate from glycolysis goes into the mitochondrial matrix—the innermost compartment of mitochondria. </span>
Answer:
What is your name?
Explanation:
no bro I don't know I am New of this app so I don't know
Distance between the focal point and the center of the lens