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3 years ago

A body is moving along a circular path with variable speed, it has both radial and tangential acceleration.

Physics

1 answer:

belka [17]3 years ago

5 0

Answer:

True; ar = v^2 / R Radial acceleration because it moves in a circular path

at = α R = tangential acceleration because its speed changes

a = at + ar total acceleration equals sum of radial and tangential

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You ride your bike from home to school, covering a distance of 3 km in 15 min. what is your average speed in km/h?

MrRa [10]

15 minutes = .25 hrs
3km/.25 hrs

3 0

3 years ago

A ladder is balanced against a wall without moving. What<br> must be true about this ladder?

Mandarinka [93]

Answer:a no net force

Explanation: google lol

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3 years ago

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien

n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

$\phi=NBA$

Put the value into the formula

$\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2$

$\phi=7.85\times10^{-7}\ Tm^2$

We need to calculate the induced emf

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{7.85\times10^{-7}}{dt}$

Put the value of emf from ohm's law

$\epsilon =IR$

$IR=\dfrac{7.85\times10^{-7}}{dt}$

$Idt=\dfrac{7.85\times10^{-7}}{R}$

$Idt=\dfrac{7.85\times10^{-7}}{0.50}$

$Idt=0.00000157=1.57\times10^{-6}\ C$

We know that,

$Idt=dq$

$dq=1.57\times10^{-6}\ C$

We need to calculate the voltage across the capacitor

Using formula of charge

$dq=C dV$

$dV=\dfrac{dq}{C}$

Put the value into the formula

$dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}$

$dV=1.57\ V$

Hence, The voltage across the capacitor is 1.57 V.

5 0

3 years ago

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the

aksik [14]

Answer:

Option A

The drag force goes up by a factor of 4

Explanation:

Fact:

Drag force is directly proportional to the square of the velocity of a moving object

Therefore, when drag force pushes opposite to the motion as one rides a bicycle, the magnitude of drag force increases by a factor of 4

3 0

4 years ago

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi

Alisiya [41]

Answer:

The force is $F = 0.1441 \ N$

Explanation:

From the question we are told that

The volume of blood ejected is $V_b = 65cm^3 = 65*10^{-6} \ m^3$

The velocity of the ejected blood is $v = 98 cm/ s = 0.98 \ m/s$

The mass density of blood is $\rho = 1060 \ kg/m^3$

The heart rate is $R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps$

Generally the average force exerted is mathematically represented as

$F = 2 * \rho * V_b * R * v$

=> $F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98$

=> $F = 0.1441 \ N$

8 0

3 years ago