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viktelen [127]
3 years ago
13

Which one of the following statements does not accurately describe vibrations?

Physics
1 answer:
Degger [83]3 years ago
8 0
Which one of the following statements does not accurately describe vibrations?
Answer: Force vibrations, such as those between a tuning fork and a large cabinet surface, results in a much lower sound than was produced by the original vibrating body.


It will help u.
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I will mark brainliest!
Anna007 [38]

Answer:

Answer is D

Explanation:

Once is bounces off the mirror it scatters

7 0
3 years ago
Read 2 more answers
La temperatura de cambio de estado, ¿Puede ser igual para todos los materiales? Justifica comparando dos materiales
Soloha48 [4]

Answer:

No.

Explanation:

Para darnos cuenta de esto tenemos que pensar en lo siguiente:

Pensemos en un vaso de vidrio, lleno de agua hasta la mitad, la otra mitad puede ser manteca derretida

Si metemos el vaso en la heladera durante un par de horas, (sabemos que la manteca en la heladera se mantiene sólida) veremos que la manteca se solidificó en la parte de arriba, mientras que el agua sigue líquida.

Entonces encontramos dos compuestos con distintas temperaturas para cambio de fase, pero materiales es más específico, y puede referirse a materiales puros.

Entonces vamos a dos metales:

Primero tenemos una pieza de hierro y una de mercurio en el congelador (supongamos que ambas están a 0°C).

Ahora los sacamos del congelador y los dejamos llegar a temperatura ambiente.

Como bien sabemos, el mercurio es líquido a temperatura ambiente, entonces el mercurio va a sufrir un cambio de fase

Ahora pensemos en el hierro; claramente va a seguir siendo sólido a temperatura ambiente, entonces podemos ver dos materiales cuyo cambio de fase de sólido a líquido ocurre en distintas temperaturas, por lo que podemos concluir que no, la temperatura de cambio de estado no puede ser igual para todos los materiales, y esto se debe a que la estructura atómica de todos los materiales es diferente.

8 0
3 years ago
Help, please
kvv77 [185]

Answer:

<em>I </em><em>am</em><em> </em><em>going</em><em> to</em><em> </em><em>answer</em><em> </em><em>the</em><em> </em><em>questions</em><em>,</em><em> according</em><em> to</em><em> the</em><em> </em><em>num</em><em>bers</em><em> </em><em>of</em><em> </em><em>empty</em><em> </em><em>spaces </em><em>to</em><em> </em><em>fill</em><em>,</em><em>1</em><em>.</em><em>e</em><em>l</em><em>e</em><em>c</em><em>t</em><em>r</em><em>i</em><em>c</em><em> </em><em>charge</em><em>,</em><em>2</em><em>.</em><em>f</em><em>o</em><em>r</em><em>c</em><em>e</em><em>,</em><em>3</em><em>.</em><em>f</em><em>i</em><em>e</em><em>l</em><em>d</em><em> </em><em>lines</em><em>,</em><em>4</em><em>.</em><em>n</em><em>e</em><em>g</em><em>a</em><em>t</em><em>i</em><em>v</em><em>e</em><em>s</em><em>,</em><em>5</em><em>.</em><em>p</em><em>o</em><em>s</em><em>i</em><em>t</em><em>i</em><em>v</em><em>e</em><em>,</em><em>6</em><em>.</em><em>a</em><em>f</em><em>f</em><em>e</em><em>c</em><em>t</em><em>e</em><em>d</em><em>,</em><em>7</em><em>.</em><em>a</em><em>t</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>,</em><em>8</em><em>.</em><em>r</em><em>e</em><em>p</em><em>e</em><em>l</em><em>.</em>

Explanation:

if u read it filling in the spaces using this answers,u will understand

5 0
2 years ago
if a diffraction grating produces a third-order bright spot for red light (of wavelength 650 nm ) at 68.0 ∘ from the central max
Mashutka [201]

Answer:

The angle is 25.34°.

Explanation:

Given that,

Wave length = 650 nm

Angle = 68.0°

We need to calculate the distance

For a diffraction grating

d\sin\theta=m\lambda

d=\dfrac{2\times650\times10^{-9}}{\sin68.0}

d=2.10\times10^{-6}\ m

We need to calculate the angle

Using formula for angle

d\sin\theta=m\lambda

\sin\theta=\dfrac{m\times\lambda}{d}

\sin\theta=\dfrac{2\times450\times10^{-9}}{2.10\times10^{-6}}

\sin\theta=25.34^{\circ}

Hence, The angle is 25.34°.

8 0
3 years ago
Three resistors of equal resistance are connected in series as shown. Compared to the voltage provided by the battery, voltage a
dsp73

Answer:

the voltage across each resistor is one third of the battery voltage

Explanation:

In a series circuit, the current is constant throughout the circuit, so the battery voltage is equal to the sum of the voltage drop in each part of the series circuit.

        V = i (R₁ + R₂ + R₃)

       

in the exercise indicate that all resistance has the same value

         R₀ = R₁ = R₂ = R₃

        V = i 3 R₀

        V = 3 V₀

         V₀ = i R₀

          V₀= V / 3

the voltage across each resistor is one third of the battery voltage

6 0
3 years ago
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