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MariettaO [177]
3 years ago
12

How are cellular respiration and photosynthesis different? (4 points)

Chemistry
1 answer:
avanturin [10]3 years ago
3 0
Answer b, cellular and photosynthesis are reversible
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Is it possible to replace our dependency on fossil fuels with alternative renewable energy's?
77julia77 [94]

Answer:

yes, coal for example produces energy by burning but there are several alternatives such as water or solar which are 2 growing energy sources.

Explanation:

hope this helps!

5 0
2 years ago
How to set up the rate expressions for the following mechanism?
Anestetic [448]

Answer:

Explanation:

From the given information:

A → B k₁

B → A k₂

B + C → D k₃

The rate law = \dfrac{d[D]}{dt}=k_3[B][C] --- (1)

\dfrac{d[B]}{dt}=k[A] -k_2[B] -k_3[B][C]

Using steady-state approximation;

\dfrac{d[B]}{dt}=0

k_1[A]-k_2[B]-k_3[B][C] = 0

[B] = \dfrac{k_1[A]}{k_2+k_3[C]}

From equation (1), we have:

\mathbf{\dfrac{d[D]}{dt}= \dfrac{k_3k_1[A][C]}{k_2+k_3[C]}}

when the pressure is high;

k₂ << k₃[C]

\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_3[C]}= k_1A \ \  \text{first order}

k₂ >> k₃[C]

\dfrac{d[D]}{dt} = \dfrac{k_3k_1[A][C]}{k_2}= \dfrac{k_1k_3}{k_2}[A][C] \ \  \text{second order}

3 0
3 years ago
What term is used for the electrons in the outermost shell
son4ous [18]

Answer:

valence electrons

Explanation:

4 0
2 years ago
Read 2 more answers
What are 3 permeable materials
gizmo_the_mogwai [7]
Permeable materials for what 
4 0
4 years ago
Read 2 more answers
Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.
STALIN [3.7K]

Answer: Solution A : [H_3O^+]=0.300\times 10^{-7}M

Solution B : [OH^-]=0.107\times 10^{-5}M

Solution C : [OH^-]=0.177\times 10^{-10}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH=-\log[H_3O^+]

pOH=-log[OH^-}

pH+pOH=14

[H_3O^+][OH^-]=10^{-14}

a. Solution A: [OH^-]=3.33\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M

b. Solution B : [H_3O^+]=9.33\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M

c. Solution C : [H_3O^+]=5.65\times 10^{-4}M

[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M

7 0
3 years ago
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