Answer:
7 valence electrons
Explanation:
Astatine has the atomic number 85. Thus, its electron configuration is:
[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p⁵
As we can see, in the last level (6) it has 2 + 5 = 7 electrons, that is, astatine has 7 electrons in its valence shell. In the Lewis dot structure (attached) we write 3 pairs of electrons and 1 unpaired electron around the symbol of At.
2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
<h3>Further explanation</h3>
Given
Standard cell notation:
Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)
Required
a balanced redox reaction
Solution
At the cathode the reduction reaction occurs, the anode oxidation reaction occurs
In reaction:
Ag⁺ + Mg → Ag + Mg²⁺
half-reactions
- at the cathode (reduction reaction)
Ag⁺ (aq) + e⁻ ---> Ag (s) x2
2Ag⁺ (aq) + 2e⁻ ---> 2Ag (s)
- at the anode (oxidation reaction)
Mg (s) → Mg²⁺ (aq) + 2e−
a balanced cell reaction
<em>2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)
</em>
Answer:
compound
Explanation:
We already know that the original substance was pure. If this substance was pure and it was powdery in nature then we have a footing to start from.
Secondly, a 4.93 g of shinny metallic liquid was left behind. This shinny metallic liquid must be an element.
Since there was a loss in mass during heating, it follows that there were other components of the pure powder.
If the reasoning stated above is correct, then the substance is a compound.
Answer:
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Answer:
MgN3
Explanation:
In MgN3 the charge on the ionic species is greater than NaCl. So,ionic interactions in MgN3 will be stronger
