Question

9. Assuming all other conditions are constant, what is the new pressure of a gas if the original pressure is 50 kPa and the Kelvin temperature is doubled?
a.100kpa
b.25kpa
or D.200kpa​

Answer 1

Answer:

Option a (100 kPa) is the appropriate option.

Explanation:

The given value is:

Original pressure,

P₁ = 50 kPa

Let the new pressure be "x".

Now,

⇒  $\frac{P1}{T_1} =\frac{P_2}{T_2}$

On substituting the values, we get

⇒  $\frac{50}{T_1} =\frac{x}{2T_1}$

On applying cross-multiplication, we get

⇒  $x = 50\times 2$

⇒     $=100 \ kPa$

Thus the answer above is the right one.