1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erik [133]
3 years ago
15

9. Assuming all other conditions are constant, what is the new pressure of a gas if the original pressure is 50 kPa and the Kelv

in temperature is doubled?
a.100kpa
b.25kpa
or D.200kpa​
Chemistry
1 answer:
notsponge [240]3 years ago
8 0

Answer:

Option a (100 kPa) is the appropriate option.

Explanation:

The given value is:

Original pressure,

P₁ = 50 kPa

Let the new pressure be "x".

Now,

⇒  \frac{P1}{T_1} =\frac{P_2}{T_2}

On substituting the values, we get

⇒  \frac{50}{T_1} =\frac{x}{2T_1}

On applying cross-multiplication, we get

⇒  x = 50\times 2

⇒     =100 \ kPa

Thus the answer above is the right one.

You might be interested in
What is the volume of NH3 produced in the following reaction when 3.0L of N2 reacts with 4.0L of H2?
trapecia [35]

Hey there !

Given the reaction:

N2 + 3 H2 = 2 NH3

At constant pressure and temperature  ,volume is proporcional to moles:

Theoretical moles of  N2 and H2 =>  1:3

Theoretical volume of N2 and H2 => 1:3

Experimental volume of N2 and H2 => 3.0 L  :  4.0 L

0.75 : 1  = 2.25 : 3

Since N2 is in excess reactant   , H2 is the limiting reactant

Therefore:

volume  of NH3 is  2/3  * Volume of H2

= 2/3 * 4.0 = 2.66 L



Hope that helps!

4 0
4 years ago
Read 2 more answers
I need help with this question please help and explain please.
enyata [817]
I would say C. (2,3). If you input the values into the equation, it works out. If you put 2 in as x and y as 3, it’s 2 + 1 = 3 which obviously works. Also, if you plot the point (2,3) on the graph, the line intersects it.
7 0
3 years ago
Will, a sprinter on the track team, has an inelastic demand for a sports drinks. The local store has raised the price of a sport
Keith_Richards [23]

He bought 10 bottles a month at $1.00 and 8 bottles a month at $1.50.

7 0
3 years ago
Nitric oxide (NO) from car exhaust is a primary air pollutant. Calculate the equilibrium constant for the reaction
viva [34]

This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:

N₂(g) + O₂(g) ⇄ 2 NO(g)

Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:

There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:

\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)

Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:

\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K

Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:

\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol

And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:

K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}

Learn more:

  • (Gibbs free energy) brainly.com/question/15213613
4 0
3 years ago
Why do liquids flow but solids dont
taurus [48]
Liquids flow because its particles can move over each other.  The particles have freedom to move and they will keep moving until it takes the shape of its container. 

Solid particles are rigid and tightly packed, they cannot move, so it does not flow.
5 0
3 years ago
Other questions:
  • Which nonmetal has the greatest potential to be oxidized
    12·1 answer
  • How are energy and mass connected during the formation of an atom?
    11·1 answer
  • Which of the following has a higher electronegativity oxygen or selenium?
    6·1 answer
  • On the basis of structure, which of the following solids has the highest melting point? Question 4 options: sucrose ,table salt
    6·2 answers
  • A phase diagram assumes ______ is kept constant
    11·2 answers
  • Anne adds granulated sugar to water and stirs it until all the sugar dissolves, leaving a sweet, transparent liquid. Under which
    11·1 answer
  • ¿por qué y para qué se utilizan las unidades de concentración?
    5·2 answers
  • What is the chemical name of the compound Cu(NO3)2? Use the list of polyatomic ions and the periodic table to help you answer.
    8·1 answer
  • A sample of oxygen gas has a volume of 130.0 ml when its pressure is 0.952 atm. What will the volume of the gas be
    12·1 answer
  • Calculate the maximum concentration (in M) of calcium ions (Ca2+) in a solution that
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!