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yan [13]
3 years ago
8

An atom that has one or two valence electrons is most likely to be - Nonreactive only

Chemistry
1 answer:
meriva3 years ago
4 0

Answer:

C) Highly reactive

Explanation:

An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion

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lilavasa [31]
An example of a fixed cell is a fat cell.
4 0
3 years ago
Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
Gwar [14]

The molarity of the solution is the moles dissolved per liter. The volume of 0.8 M citric acid solution will be 74.16 mL.

<h3>What is molarity?</h3>

Molarity of the solution is the concentration that is given by the moles of the solute that are dissolved to make the solution in liters.

The chemical reaction between baking soda and citric acid is shown as:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Given,

Molarity = 0.8 M

Mass of baking soda = 15 grams

The molar mass of baking soda = 84.007 g/mol

Moles of baking soda = 15 ÷ 84.007 = 0.178 moles

From the reaction, it can be said that 3 moles of baking soda are required to react with 1 mole of citric acid. So, 0.178 moles will need, 0.059 moles.

The volume of citric caid needed is calculated as:

M = moles ÷ volume

Volume (L) = 0.059 ÷ 0.8

= 0.07416 L

Volume is converted into mL as:

1 L = 1000 mL

0.07416 L = 74.16 mL

Therefore, 74.16 mL is the volume of citric acid needed.

Learn more about molarity here:

brainly.com/question/7145257

#SPJ1

5 0
2 years ago
what is the suggested weight of the sample that should be disssolved in the beaker before it is transferred to the NMR tube
sukhopar [10]
The sample must be sufficiently soluble (fig. 2) to yield an NMR spectrum. For 1H and 1H observed NMR, it is recommended to dissolve between 2 and 10 mg in between 0.6 and 1 mL of solvent so that the sample depth is at least 4.5 cm in the tube (fig. 3).
3 0
2 years ago
How much energy is required to vaporize 155 g of butane at its boiling point? the heat of vaporization for butane is 23.1 kj/mol
netineya [11]

The energy required to vaporize 155 g of butane at its boiling point: 61,723 kJ

<h3>Further explanation</h3>

Enthalpy is the amount of system heat at constant pressure.

The enthalpy is symbolized by H, while the change in enthalpy is the difference between the final enthalpy and the initial enthalpy symbolized by ΔH.

\large{\boxed{\boxed{\bold{\Delta H=H_{End}-H_{First}}}}

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The standard unit is kilojoules (kJ)

The enthalpy change symbol (ΔH) is usually written behind the reaction equation.

Change in Standard Evaporation Enthalpy (ΔH vap) is a change in enthalpy at the evaporation of 1 mol liquid phase to the gas phase at its boiling point and standard pressure.

Examples of water evaporation:

 H₂O (l) ---> H₂O (g); ΔH vap = + 44kJ

The enthalpy of evaporation is positive because its energy is needed to break the attraction between molecules in a liquid

  • 155 g of butane

relative molecular mass of butane (C₄H₁₀) = 4.12 + 10.1 = 58 gram / mol

tex]\large{\boxed{mole\:=\:\frac{grams}{relative\:molecular\:mass}}}[/tex]

\large mole\:=\:\large \frac{155}{58}

mole = 2,672

Since the heat of vaporization for butane is 23.1 kj / mol, the energy needed to evaporate 2,672 moles of butane is:

23.1 kJ / mol x 2,672 mol = 61,723 kJ

<h3>Learn more</h3>

the heat of vaporization

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The latent heat of vaporization

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Keywords: the heat of vaporization, butane, mole, gram, exothermic, endothermic

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4 years ago
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Help me plzz I need help ​
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