Question

Solve the equation for all values of x. (8x+9)(49x^2-100)=0

Answer 1

Answer:

$x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}$

Step-by-step explanation:

8x+9=0

8x=-9

$x = \frac{-9}{8}$

or

$49x^{2}-100 = 0$

$(7x)^{2} -10^{2} =0$,

$(7x+10)(7x-10)=0$

$7x+10=0, 7x-10=0$

$7x=-10, 7x=10$

$x=-\frac{-10}{7}$, $x = \frac{10}{7}$