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pshichka [43]
3 years ago
9

The lines in the emission spectrum of hydrogen result from __________.

Physics
1 answer:
Annette [7]3 years ago
8 0

Answer:

Option (a) is correct.

Explanation:

The lines in the emission spectrum of hydrogen is due to the transfer of electrons form higher energy levels to the lower energy levels.

When the electrons transfer from one level of energy that is higher level of energy to the other means to the lower level of energy then they emit some photons which having the frequency or the wavelength in the visible region.

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A hammer falls from a construction worker's hand 30m above the ground at the same time that a filled soft drink can is projected
drek231 [11]

For harmer:-

initial velocity=u=0m/s

Acceleration due to gravity=10m/s^2

Now

\\ \sf\longmapsto s=ut+\dfrac{1}{2}gt^2

\\ \sf\longmapsto s=0t+\dfrac{1}{2}(10)t^2

\\ \sf\longmapsto s=5t^2\dots(1)

For soft drink:-

u=24m/s

\\ \sf\longmapsto 30-s=(24)t+\dfrac{1}{2}(10)t^2

Using eq(1)

\\ \sf\longmapsto 30-5t^2=24t-5t^2

\\ \sf\longmapsto 24t=30

\\ \sf\longmapsto t=\dfrac{30}{24}

\\ \sf\longmapsto t=1.2s

After 1.2s they will meet.

Now

putting t in eq(1)

\\ \sf\longmapsto s=5t^2=5(1.2)^2=5(1.44)=7.2m

At the height of 7.2m they will meet

3 0
3 years ago
A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms
Aleonysh [2.5K]

Explanation:

It is given that,

Power of EM waves, P = 1800 W

We need to find the intensity at a distance of 5 m. Also, the rms value of the electric field.

Intensity,

I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{1800}{4\pi\times (5)^2}\\\\I=5.72\ W/m^2

The formula that is used to find the rms value of the electric field is as follows :

I=\epsilon_o cE^2_{rms}

c is speed of light and \epsilon_o is permittivity of free space

So,

E_{rms}=\sqrt{\dfrac{I}{\epsilon_o c}}\\\\E_{rms}=\sqrt{\dfrac{5.72}{8.85\times 10^{-12}\times 3\times 10^8}}\\\\E_{rms}=46.41\ V/m

Hence, this is the required solution.

4 0
3 years ago
A driver of a car traveling 14.6 m/s must slam on the brakes to avoid hitting a black bear crossing the road. If it takes 3.00 s
SVETLANKA909090 [29]

Answer:

a = (V2 - V1) / t = (0 - 14.6) / 3 = -4.87 m/s^2

It might be useful to convert 14.6 m/s to mph

14.6 m/s * 39.37 in/m = 575 in /s

575 in/s / 12 in/ft = 47.9 ft/sec

47.9 ft/s / 88 ft/sec *  60 mph = 32.6 mph

7 0
3 years ago
Before leaving her home, Myesha makes sure that every electrical appliance is unplugged and checks that every window and door is
Kryger [21]

Answer:Obsessive-Compulsive Disorder

Explanation:

Obsessive-Compulsive Disorder is a general, persistent, and soon-lasting disorder in which an individual has involuntary, repetitive thoughts and/or actions that he or she feels compelled to replicate over and over.

Myesha also shows the symptoms of OCD by constantly checking the window and doors.

An individual suffering from OCD shows symptoms like

  • Fear of or infection by germs
  • Aggressive feelings to others or self
  • Getting things in a symmetrical or optimal order  
8 0
3 years ago
A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is
mihalych1998 [28]

Answer:

a) v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

b) \theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

c)t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

d) Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that v_y = 2 m/s represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is V_x= 4.8 m/s

And we want to find the velocity of the motord board relative to the Earth v_m

And we can find this velocity from the Pythagorean Theorem.

v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

Part b

We can find the direction with the following formula:

\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

D = Vt

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

Part d

For this case we can use the same definition but now using the y compnent we have:

Y = v_y t

And replacing we got:

Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

7 0
3 years ago
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