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3 years ago

Pls help what is this as a simplified fraction (thank u Jesus loves u)

Mathematics

1 answer:

GaryK [48]3 years ago

6 0

Answer:

-500/11

Step-by-step explanation:

0.22 in fraction is 11/50

After replacing the decimal with a fraction, subtract it from -10.

You'll have -10÷(11/50)

You'll then change the division sign to a multiplication sign.

You'll then have that -10 × 50/11

-10×50 = -500/11.

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A student says that if 5x2 = 20, then x must be equal to 2. Do you agree or disagree with the student? Justify your answer.

Llana [10]

I disagree. If each side of the equation is divided by 5, the result is x2 = 4. By the square root property of equality, x = -2 or x = 2. So x could be -2 instead of 2.

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3 years ago

Read 2 more answers

What's a real number between -1/10 and 0?

vova2212 [387]

Answer:

The answer is at the bottom!!

Step-by-step explanation:

And All of those Natural Numbers will be starting with 1 so we will be having other Numbers as well on which No Number will be mapped like 2 or 211 or 79 So This Means Set of Natural Numbers is Grater then Real Numbers Between 0 and 1. So Set of Real Numbers Between 0 and 1 is Countably Infinite.

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3 years ago

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3 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

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3 years ago

Consider the graph shown. Which of the following does not represent the rate of change found when using similar triangles? Choos

Luba_88 [7]

Answer:

C and D

Step-by-step explanation:

since the line is going up from points A to D it cannot be a negative number.

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