Explanation:
formula for energy is k. e = ½mv²
m= 9
v= 75
k. e = ½×9×75 =337•5
Answer:
2500m
Explanation:
given,
initial velocity(u) = 5m/s
final velocity (v) = 0 m/s ( as he/she stopped riding after 1000 secs)
time = 1000 secs
distance(s)=?
now,
s=( u+v ) ×t /2
=(5+0)×1000/2
=2500 m
hence, he /she travels 2500m far
Answer:
The critical stress required for the propagation of an initial crack
= 21.84 M pa
Explanation:
Given data
Modulus of elasticity E = 225 ×

Specific surface energy for magnesium oxide is
= 1 
Crack length (a) = 0.3 mm = 0.0003 m
Critical stress is given by
=
-------- (1)
⇒ 2 E
= 2 × 225 ×
× 1 = 450 ×
⇒
a = 3.14 × 0.0003 = 0.000942
⇒ Put these values in equation 1 we get
⇒
=
⇒
= 4.77 × 
⇒
= 2.184 ×

⇒
= 21.84 
⇒
= 21.84 M pa
This is the critical stress required for the propagation of an initial crack.