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Oduvanchick [21]
3 years ago
11

A ten loop coil of area 0.23 m2 is in a 0.047 T uniform magnetic field oriented so that the maximum flux goes through the coil.

The average emf induced in the coil is
Physics
1 answer:
andrezito [222]3 years ago
4 0

Answer:

Explanation:

From the question we are told that:

Number of turns N=10

Area a=0.23m^2

Magnetic field B=0.947T

Generally the equation for maximum flux is mathematically given by

 \phi=NBa

 \phi=10*0.047*0.23

 \phi=0.1081wbi

Therefore induced emf

 e= \frac{d\phi}{dt}

Since

 t=0

Therefore

 e=0

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Explanation:

Given that,

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We need to find the impulse received by the ball. The impulse delivered is given by :

J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

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A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball's acceleration?
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Explanation:

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a = Δv / t        ----------------(i)

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a = acceleration (measured in m/s²)

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t = time taken for the change (measured in seconds(s))

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Answer:

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Hello.

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