Answer:
3t
Step-by-step explanation:
7t-3t+4t-5t
Combine like terms
7t -3t = 4t and substitute back into the expression
4t +4t -5t
4t+4t = 8t and substitute back into the expression
8t - 5t
3t
350 calories lost per day and there are 3,500 calories in a pound
350x10=3,500
it will take Judy 100 days to lose 10 pounds.
Answer:
37 - 56 lb / ft3
0.6 - 0.9 103 kg / m3
Step-by-step explanation:
The density or hardness of wood varies by species, and the value is necessary to approximate the weight of lumber by volume. In this table, the density of different species of wood is expressed as weight in pounds per cubic foot and kilograms per cubic meter. The density will vary based on the moisture content of the wood.
Its false, standard notation would have an exponent.
With the curve
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parameterized by

with
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, and given the vector field

the work done by

on a particle moving on along
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is given by the line integral

where

The integral is then

