The heaviest planet in the world is Jupiter!
Thank you for posting your question here at brainly. I think your question is incomplete. Below is the complete question, it can be found elsewhere:
What is the probability of finding an electron within one Bohr radius of the nucleus?<span>Consider an electron within the 1s orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by 1-a0^2[a0^2-e^(-2R/a0)(a0^2+2a0R+2R2)]. Where a0 is the Bohr radius (for a hydrogen atom, a0 = 0.529 Å.). What is the probability of finding an electron within one Bohr radius of the nucleus? What is the probability of finding an electron of the hydrogen atom within a 2.30a0 radius of the hydrogen nucleus?
Below is the answer:
</span><span>you plug the values for A0 and R into your formula</span>
The answer should be flammability
Answer:
here's the pdf for it
IB QuestionbankExplanation:
<span>3.834 m/s.
In this problem we need to have a centripetal force that is at least as great as the gravitational attraction the object has. The equation for centripetal force is
F = mv^2/r
and the equation for gravitational attraction is
F = ma
Since m is the same in both cases, we can cancel it out and then set the equations equal to each other, so
a = v^2/r
Substitute the known values (radius is diameter/2) and solve for v
9.8 m/s^2 <= v^2/1.5 m
14.7 m^2/s^2 <= v^2
3.834057903 m/s <= v
So the minimum velocity needed is 3.834 m/s.</span>
