Answer:
1680 seconds
Explanation:
The pitch of a sound is most closely related to the what
1 answer:
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Answer:
time is 3333.33 min or 55.55 hr
Explanation:
given data
reactor operating = 1 MW
negative reactivity = $5
power = 1 miliwatt
to find out
how long does it take
solution
we know here power coefficient that is
power coefficient =
power coefficient = 1
so time required to reach power is
power = reactivity × time / power coefficient + reactor operating
1 × = -5 t / 1 + 1 ×
5t = -
t = 199999.99 sec
so time is 3333.33 min or 55.55 hr
Refer to the diagram shown below.
Neglect wind resistance, and use g = 9.8 m/s².
The pole vaulter falls with an initial vertical velocity of u = 0.
If the velocity upon hitting the pad is v, then
v² = 2*(9.8 m/s²)*(4.2 m) = 82.32 (m/s)²
v = 9.037 m/s
The pole vaulter comes to res after the pad compresses by 50 cm (or 0.5 m).
If the average acceleration (actually deceleration) is (a m/s²), then
0 = (9.037 m/s)² + 2*(a m/s²)*(0.5 m)
a = - 82.32/(2*0.5) = - 82 m/s²
Answer: - 82 m/s² (or a deceleration of 82 m/s²)
Neglect wind resistance, and use g = 9.8 m/s².
The pole vaulter falls with an initial vertical velocity of u = 0.
If the velocity upon hitting the pad is v, then
v² = 2*(9.8 m/s²)*(4.2 m) = 82.32 (m/s)²
v = 9.037 m/s
The pole vaulter comes to res after the pad compresses by 50 cm (or 0.5 m).
If the average acceleration (actually deceleration) is (a m/s²), then
0 = (9.037 m/s)² + 2*(a m/s²)*(0.5 m)
a = - 82.32/(2*0.5) = - 82 m/s²
Answer: - 82 m/s² (or a deceleration of 82 m/s²)