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Paha777 [63]
3 years ago
15

Help me please !!!!!

Physics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

confounding cause they had exposure to many programmes

kipiarov [429]3 years ago
3 0

Answer:

Confounding should be your answer please mark brainliest

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The true brightness of an object is called its
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3 years ago
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when you're in your house and hear a car drive by outside, how many different mediums do sound waves from the car engine have to
snow_lady [41]

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As the sound approaches, it gets louder (simply because you're closer to the source), and has a higher pitch. Then, as it passes, the sound suddenly dips down, and as it drives away you hear a lower pitch, plus a decreasing volume as the engine gets farther and farther away.

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2 years ago
Which formula can be used to find the tangential speed of an orbiting object?
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The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
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6 0
3 years ago
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shows two parallel nonconducting rings with their central axes along a common line. Ring 1 has uniform charge q1 and radius R; r
Ainat [17]

Answer:

\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}

Explanation:

Given that

Charge on ring 1 is q1 and radius is R.

Charge on ring 2 is q2 and radius is R.

Distance ,d= 3 R

So the total electric field at point P is given as follows

Given that distance from ring 1 is R

\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(d-R)}{(R^2+(d-R)^2)^{3/2}}=0

\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(3R-R)}{(R^2+4R^2)^{3/2}}=0

\dfrac{q_1R}{(2R^2)^{3/2}}-\dfrac{q_2(2R)}{(5R^2)^{3/2}}=0

\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}

8 0
3 years ago
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The resulting net force of an object is represented below.
yKpoI14uk [10]

Answer:

← 63 N and → 73 N

Explanation: i think plz tell me if im wrong

4 0
2 years ago
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