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mariarad [96]
3 years ago
9

He had 5 dogs plus 2. Cats How many did he have all together?

Physics
2 answers:
IRISSAK [1]3 years ago
7 0
He had in total 7 cats and dogs.
brilliants [131]3 years ago
4 0
7 animals in total
i hope i understood your question...
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01. Um carrinho de massa 10 kg é empurrado, horizontalmente, sobre uma superfície plana horizontal, com força constante de 20 N.
Lostsunrise [7]

Responder:

<h2>D. 1.5m / s² </h2>

Explicación:

Usaremos la segunda ley de movimiento de Newton para resolver esta pregunta. De acuerdo con el teorema

es la suma de las fuerzas que actúan sobre el cuerpo a lo largo de la horizontal. Las dos fuerzas son la fuerza móvil (Fm) y la fuerza de fricción (Ff).

Fm = 20 N y Ff = 5 N

\sum Fx = ma_x\\\sum Fx = Fm - Ff\\\sum Fx  = 20N - 5N\\\sum Fx  = 15N

m es la masa del cuerpo = 10 kg

El parámetro requerido es cuál es la aceleración del cuerpo a lo largo de la horizontal.

De la ecuación 1;

a_x = \sum Fx/m\\\\a_x = 15/10\\\\a_x = 1.5m/s^2

Por lo tanto, la aceleración del carro es de 1.5 m / s²

3 0
4 years ago
The kinetic energy of the attracted magnet and iron rod came from potential energy in the system.
Yuri [45]

Answer:

The amount of potential energy stored in the magnetic field depends on both the strength of the magnet and the distance that another magnet or magnetic object is from it. ...

Explanation:

All objects have a gravitational force, no matter how small, but only some objects such as iron objects can have a magnetic force.

3 0
3 years ago
Read 2 more answers
Do you think there is magnus force acting on the earth
Aleonysh [2.5K]
I think so but am not sure
6 0
3 years ago
Calculate the final velocity right after a 117 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padd
Free_Kalibri [48]

Answer:

v_f = 0.87 m/s

Explanation:

We are given;

F_avg = -17700 N (negative because it's backward)

m = 117 kg

Δt = 5.50 × 10^(−2) s

v_i = 7.45 m/s

Now, formula for impulse is given by;

I = F•Δt = - 17700 x 5.50 × 10^(−2) = - 973.5 kg.m/s

From impulse momentum theory, we know that;

Change in momentum of particle is equal to impulse.

Thus,

Δp = I = m•v_f - m•v_i

Thus,

-973.5= 117(v_f - 7.45)

Thus,

-973.5/117 = (v_f - 7.45)

-8.3205 + 7.45 = v_f

v_f = - 0.87 m/s

We'll take absolute value as;

v_f = 0.87 m/s

5 0
4 years ago
A horizontal force of magnitude 356 N is employed to push a 78.0-kg block a distance of 18.6 m on a rough horizontal surface. If
icang [17]

Answer:

6621.6 Joule

0.46525

Explanation:

F = Force = 356 N

s = Displacement = 18.6 m

m = Mass of block = 78 kg

Work done

W=F\times s\\\Rightarrow W=356\times 18.6\\\Rightarrow W=6621.6\ J

The work done by the horizontal force is 6621.6 Joule

F=\mu mg\\\Rightarrow \mu=\frac{F}{mg}\\\Rightarrow \mu=\frac{356}{78\times 9.81}\\\Rightarrow \mu=0.46525

The coefficient of friction between the block and the rough surface is 0.46525

5 0
3 years ago
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