-- There are 80 protons in the nucleus of every atom of Mercury,
but only 8 of them in the nucleus of an atom of Oxygen.
-- Mercury must be warmer than 357°C in order to boil, but Oxygen
must only be warmer than -183°C.
-- Mercury must be colder than -39°C in order to freeze, but Oxygen
must be colder than -219°C.
-- Oxygen is required for human life. Mercury is a deadly poison.
Surface tension can change with the change in a medium that is just above the layer of the liquid's surface.
Explanation:
Pouring any oil or oily compounds (such as kerosene) on the free surface of the water will reduce the surface tension.
in the atmosphere directly affects the surface tension of the liquid.
If we increase the temperature of the water, then there is a high possibility of the surface tension of the water getting reduced, due to the fact that the net force of attraction is decreased.
Mixing surfactants or emulsifiers into the water will decrease the surface tension.
If the water is subjected to electrification, then the surface tension will be reduced.
It depends on what it is closest to but I would say for instance black is 5 points and red is 6 if u land on the line 5.5
Answer:
12 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 7.6 kg
Distance (d) = 6 m
Velocity (v) = 5 m/s
Force (F) = 2 N
Workdone (Wd) =.?
Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:
Workdone = Force × distance
Wd = F × d
With the above formula, we can obtain the workdone as follow:
Distance (d) = 6 m
Force (F) = 2 N
Workdone (Wd) =.?
Wd = F × d
Wd = 2 × 6
Wd = 12 J
Thus, the workdone is 12 J
Answer: 1.91*10^8 N/m²
Explanation:
Given
Radius of the steel, R = 10 mm = 0.01 m
Length of the steel, L = 80 cm = 0.8 m
Force applied on the steel, F = 60 kN
Stress on the rod, = ?
Area of the rod, A = πr²
A = 3.142 * 0.01²
A = 0.0003142
Stress = Force applied on the steel/Area of the steel
Stress = F/A
Stress = 60*10^3 / 0.0003142
Stress = 1.91*10^8 N/m²
From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²
