Please help I’m depending on this so I can pass

given two squares, one with side length of 5 and the other with a side length of 7, what is the ratio of their areas?

Kaylis [27]

Answer:

25: 49

Step-by-step explanation:

$5*5:7*7\\25: 49$

7 0

3 years ago

A general formula for a parabola is x2 = 4py. What is the value of p in the equation x2 = 12y? p =

stepladder [879]

Answer:

p=3

Step-by-step explanation:

The given parabola has equation ;

$x^2=12y$

The general formula for a parabola is;

$x^2=4py$

To find the value of p, we need to compare the coefficient of y in both equations;

$\implies 4p=12$

Divide both sides by 4;

$\implies p=\frac{12}{4}$

$\implies p=3$

5 0

3 years ago

Which is a better buy 4 grapefruits for 80 cents or 12 grapefruits for $1.80?

PtichkaEL [24]

12 grapefruit for 1.80. so if you multiply. 80 cents by 3=2.40 for 12 but 1.80 us cheaper

8 0

3 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.