Juan has blue cubes with a 55 mm edge and red cubes with a 45 mm edge. He stacks them in two columns, one of each color; he wants the two columns to be the same height. How many cubes does he need, as a minimum, of each color?

Let

x---------> the number of blue cubes

y--------> the number of red cubes

we know that

Juan wants that the two columns to be the same height

$55x=45y$

solve for y

$y=\frac{55}{45}x$

I proceed to calculate a table, assuming values of x to calculate the value of y. When the values of x and y are whole numbers, I will have found the solution.

the table in the attached figure

therefore

<u>the answer is</u>

9 blue cubes

11 red cubes

7 0

3 years ago

Define the domain: {(2,3),(0,3),(4,2),(5,6)}

Y_Kistochka [10]

For the following relation the domain would be all of the x coordinates.
D=A. 2,0,4,5

5 0

2 years ago