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romanna [79]
3 years ago
6

How many moles of NH₃ can be produced from 4.81 moles of nitrogen in the following reaction:

Chemistry
1 answer:
makkiz [27]3 years ago
8 0

Answer:

9.62moles of NH₃

Explanation:

Given parameters:

Number of moles of nitrogen  = 4.81moles

Unknown:

Number of moles of  NH₃ = ?

Solution:

To solve this problem, we need to establish a balanced reaction equation:

            N₂  +  3H₂  →  2NH₃

Now, we can solve the problem by working from the known to the unknown.

          1 mole of N₂ produced 2 moles of NH₃

         4.81moles of N₂ will produce 2 x 4.81  = 9.62moles of NH₃

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7. What is the total pressure of the following mixture of gases in a 20.0 L container at 298 K: 12.0 g He,
zloy xaker [14]

Answer:

P(total) = 14.81 atm

Explanation:

According to the Dalton law of partial pressure,

The pressure exerted by mixture of gases are equal to the sum of partial pressure of individual gases.

P(total) = P1 + P2 + P3+ .....+ Pn

Given data:

Volume of container = 20.0 L

Temperature = 298 K

Mass of He = 12.0 g

Moles of hydrogen = 4.00 mol

Pressure of Ne = 6.25 atm

Solution:

Moles of helium:

Number of moles = mass/molar mass

Number of moles = 12 g/ 4 g/mol

Number of moles = 3 mol

Pressure of helium:

PV = nRT

P = nRT/ V

P = 3 mol × 0.0821 atm.L. mol⁻¹.k⁻¹ × 298 K / 20 L

P = 73.4 atm / 20

p = 3.67 atm

Pressure of hydrogen:

PV = nRT

P = nRT/ V

P = 4 mol × 0.0821 atm.L. mol⁻¹.k⁻¹ × 298 K / 20 L

P = 97.86 atm / 20

P = 4.89 atm

Total pressure:

P(total) = P(He) + P(Ne) + P(H₂)

P(total) = 3.67 atm + 6.25 atm + 4.89 atm

P(total) = 14.81 atm

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NeX [460]
A.
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B.
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C.
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the right side - 2 atoms of hydrogen, 4 atoms of oxygen
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D.
the left side - 2 atoms of hydrogen, 1 atom of oxygen
the right side - 4 atoms of hydrogen, 4 atoms of oxygen
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