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3 years ago

How many moles of NH₃ can be produced from 4.81 moles of nitrogen in the following reaction:

Chemistry

1 answer:

makkiz [27]3 years ago

8 0

Answer:

9.62moles of NH₃

Explanation:

Given parameters:

Number of moles of nitrogen = 4.81moles

Unknown:

Number of moles of NH₃ = ?

Solution:

To solve this problem, we need to establish a balanced reaction equation:

N₂ + 3H₂ → 2NH₃

Now, we can solve the problem by working from the known to the unknown.

1 mole of N₂ produced 2 moles of NH₃

4.81moles of N₂ will produce 2 x 4.81 = 9.62moles of NH₃

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Diuris are common orchids found in Australia. The flowers of this species display a large number of variations in color and mark

Strike441 [17]

From what we know, we can confirm that the variations in colors are a mechanism intended to protect the plants from predators.

<h3>Why is color a protection mechanism?</h3>

This can be observed throughout nature. Many poisonous organisms have evolved bright colors intended to be noticed. Over time, this has resulted in many predators avoiding prey with bright colors, in order to avoid the possibility of being poisoned.

Therefore, we can confirm that the variations in colors are likely a mechanism intended to protect the plants from predators.

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2 years ago

What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)? Show your work or explain the steps that you used t

timurjin [86]

First, we will get the number of moles:
one mole contains Avogadro's number of atoms. Therefore, to know the number of moles in <span>7.83 × 10^24 atoms, we will simply do cross multiplication as follows:
number of moles = (</span><span>7.83 × 10^24*1) / (6.022 * 10^23) = 13 moles

From the periodic table:
mass of one mole of helium = 4 grams
Therefore:
mass of 13 moles of helium = 13*4 = 52 grams</span>

7 0

4 years ago

Hydrazine (N2H4) is used as rocket fuel. It reacts with oxygen to form nitrogen and water.

Marina86 [1]

Answer:

See explanation below for answers

Explanation:

This is a stochiometry reaction. LEt's write the overall reaction again:

N₂H₄ + O₂ ---------> N₂ + 2H₂O

This reaction is taking place at Standard temperature and pressure conditions (STP) which are P = 1 atm and T = 273 K. To know the volume of N₂ formed, we need to know first how many moles are formed, and this can be calculated with the reagents and the limiting reagent. Let's calculate the moles first of the reagents:

MM N₂H₄ = 32 g/mol; MM O₂ = 32 g/mol

mol N₂H₄ = 2000 / 32 = 62.5 moles

mol O₂ ? 2100 / 32 = 65.63 moles

Now that we have the moles, we need to apply the stochiometry and calculate the limiting reagent. According to the overall reaction we have a mole ratio of 1:1 between N₂H₄ and O₂, therefore:

1 mole N₂H₄ ---------> 1 mole O₂

62.5 moles ----------> X

X = 62.5 moles of O₂

But we have 65.63 moles, therefore, the limiting reactant is the N₂H₄.

We also have a 1:1 mole ratio with the N₂, so:

moles N₂H₄ = moles N₂ = 62.5 moles

Now that we have the moles, we can calculate the volume with the ideal gas equation:

PV = nRT

V = nRT / P

R: gas constant (0.082 L atm / K mol)

Replacing we have:

v = 62.5 * 0.082 * 273 / 1

V = 1399.13 L of N₂

Now, how many grams of the excess remains?, we know how many moles are reacting so, let's see how much is left:

moles remaining = 65.63 - 62.5 = 3.12 moles

then the mass of oxygen:

m = 3.12 * 32 = 100.16 g of O₂

7 0

3 years ago

Read 2 more answers

Indicate how the concentration of each species in the chemical equation will change to reestablish equilibrium after changing th

Viktor [21]

Explanation:

Since this is an equilibrium problem, we apply le chatelier principle. This principle states that whenever a system at equilibrium is disturbed due to change in several factors, it would move in a way to annul such change.

C2H4(g) + Cl2 ⇔ 2C2H4Cl2(g)

When the concentration of C2H4 is increased, there is more reactant sin the system. In order to annul this change, the equilibrium position will shift to the right favoring product formation.

When the concentration of C2H4Cl2 is increased, there is more product in the system. To annul this change, the equilibrium position will shift to the left, favoring reactant formation.

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3 years ago

At 293 K, methanol has a vapor pressure of 97.7 Torr and ethanol has a vapor pressure of 44.6 Torr. What would be the vapor pres

Bad White [126]

Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_1=x_1p_1^0$ and $p_2=x_2P_2^0$