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2 years ago

What is The temperature at which a substance changes from a liquid to a gas

Chemistry

2 answers:

Rainbow [258]2 years ago

6 0

The melting point for ice is at 32 degrees <span>Fahrenheit or O degrees Celsius.</span>

Zielflug [23.3K]2 years ago

3 0

In terms of what it is called, this refers to the boiling point. It is at this temperature does the liquid phase change occur to gas.

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A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31

Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

$PV = nRT$

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

$n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles$

Now, we can find the temperature with the final conditions:

$T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K$

The temperature in Celsius is:

$T_{2} = 274.7 - 273 = 1.7 ^{\circ} C$

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!

8 0

2 years ago

adam wants to investigate the strengths of different acids and alkalis. He has 2 different acid solutions and 2 different alkali

SCORPION-xisa [38]

Answer:

The strength of an acid or alkali depends on the degree of dissociation of the acid or alkali in water. The degree of dissociation measures the percentage of acid molecules that ionise when dissolved in water. He could use universal indicators or litmus paper for this.

Explanation:

(See answer for the explanation)

5 0

2 years ago

What is the empirical formula of a compound that is 41.4% Strontium, 13.24%

Pepsi [2]

Answer:

Empirical Formula N2O6Sr Strontium Nitrate

Explanation:

N=13.2% O=45.4% Sr=41.4%

6 0

2 years ago

: calculate the mass of the solute in 1.500 l of 0.30 m glucose, c6h12o6, used for intravenous injection

vfiekz [6]

Answer is: <span>the mass of the glucose is 81,07 grams.
</span>c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.

8 0

3 years ago

0.500 mile of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (

SCORPION-xisa [38]

The correct question is as follows: 0.500 moles of potassium oxide is dissolved in enough water to make 2.00 L of solution. Calculate the molarity of this solution (plz help!)

Answer: The molarity of this solution is 0.25 M.

Explanation:

Molarity is the number of moles of a substance divided by volume in liter.

As it is given that there are 0.5 moles of potassium oxide in 2.00 L of water so, the molarity of this solution is calculated as follows.

$Molarity = \frac{moles}{volume(in L)}\\= \frac{0.5 moles}{2.00 L}\\= 0.25 M$

Thus, we can conclude that molarity of this solution is 0.25 M.

4 0

2 years ago