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3 years ago

2x+y=8;y i have no idea what theyre asking. Its solve each equation for the indicated variable

1 answer:

8 0

If solving for y:

→ 2x + y = 8
→ Take away 2x from both sides
→ y = 8 - 2x

If solving for x:

→ 2x + y = 8
→ Take away y from both sides
→ 2x = 8 - y
→ Divide both sides by 2
→ x = $\frac{8-y}{2}$

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Because of an increase of 4% in wholesale prices, a shoe store had to mark up its new stock by the same percent. What was the ne

Mamont248 [21]

Answer:the new price of the shoe is $5

Step-by-step explanation:

The price at which the shoe has been selling is $25.

Because of an increase of 4% in wholesale prices, a shoe store had to mark up its new stock by the same percent. The value of the 4% increase on the initial price of the shoe is

4/100 × 25 = 0.04 × 25 = $1

Therefore, the new price of the shoe would be

4 + 1 = $5

8 0

4 years ago

How many star are there universe

rjkz [21]

Answer:

there is no number for that,there is infinite stars in the universe

3 0

4 years ago

Read 2 more answers

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago

I need help on sketching the graph

frozen [14]

So the first thing to do is get two points. Lets start easy lets plug in 0 for x
$y = 2(0) + 1 \\ y = 1$
We get the point (0, 1).
Now plug in 2 for x
$y = 2(2)+ 1 \\ y = 5$
So the two points are (0, 1) and (2, 5)
Now from those two points draw a straight line

8 0

3 years ago

What is 2/5% of 820? 1.8 2.05 2.88 3.28

Margarita [4]

Answer:

D) 3.28

Step-by-step explanation:

820/x=100/2.5

(820/x)*x=(100/2.5)*x - we multiply both sides of the equation by x

820=40*x - we divide both sides of the equation by (40) to get x

820/40=x

20.5=x

x=20.5

now we have:

2.5% of 820=20.5

6 0

3 years ago