So to start off, first combine like terms, so all the a^2 with the a^2’s, the a’s with the a’s, and the normal numbers.
Add the -5a^2, the -a^2, and the -18a^2 together.
-24a^2-12a-6a-4-16+5a
Now add the -12a, the -6a, and the 5a together.
-24a^2-13a-4-16
Lastly add the -4 and -16 together.
-24a^2-13a-20
^^That is your answer^^
Hope this helps!
A group of friends spent 1, 0, 2, 3, 4, 3, 6, 1, 0, 1, 2, and 2 hours online last night. What are the 1st and 3rd quartiles for
Ostrovityanka [42]
Arrange the numbers from smallest to largest:
0,0,1,1,1,2,2,3,3,4,6
Split the data in the middle, since there is an odd amount of numbers take an even amount on each side:
0,0,1,1,1,2,2,3,3,4,6
Lower half: 0,0,1,1,1
Higher half: 2,3,3,4,6
1st quartile is the middle value of the lower half: 1
3rd quartile is the middle value of the higher half: 3
The answer is g(x) = 3x - 6
Answer:
1 donut and a bag of coffee costs $4.50
Step-by-step explanation:
Start by creating a pair of simultaneous equations.
Let
a donut.
Let
a bag of coffee.
Therefore:


There are a few ways to solve these equations. This time I'll show you the elimination method. We eliminate one of the variables to get the other variable equal to a number.
Start by multiplying one of the equations by a number so that one of the variables has the same coefficient (number at the front) as the same variable in the other equation.
I'll multiply the second equation by 2 so that the
will have a coefficient of 2 like the 1st equation.
,
.
Now we have two equations with the same coefficient of
. We can subtract the equations from each other to eliminate the
variable and leave
equal to a number.
Subtracting
and
:

Simplify to get
.
Therefore
.
Now we have one of the variables, we can find the other variable by putting the known variable back into one of the equations.
- original equation
- substituting
.
- simplifying
- re-arranging to solve for 
Therefore,
and
.
So 1 donut costs $1.50 and 1 bag of coffee costs $3.
1 donut and a bag of coffee costs $4.50