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2 years ago

Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second.

Mathematics

1 answer:

stellarik [79]2 years ago

4 0

Assuming that the is number seconds, it would be 28.0957

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Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevat

natta225 [31]

Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50° to the nearest foot the streetlamp is about 26 feet tall.

I hope this helps!

4 0

2 years ago

Sam built a fence that was 54 feet long she built the same legnth of fence each day for 6 days how many inches of fence did Sam

FromTheMoon [43]

Answer:

9 inches a day

Step-by-step explanation:

9 multiplied by 6 is 54

4 0

2 years ago

Read 2 more answers

The total cost of $4 sharpeners and $7 folders is $30.05. If the cost of a sharpener is $a, and a folder is $2.80 more expensive

raketka [301]

9514 1404 393

Answer:

a = $0.95

Step-by-step explanation:

The cost of a sharpener is 'a', and the cost of a folder is $2.80 more, so is a+2.80. The total cost of 4 sharpeners and 7 folders is ...

4a +7(a+2.80) = 30.05

11a = 10.45 . . . . . . . . . . . subtract 19.60

a = 0.95 . . . . . . . . . . . divide by 11

The cost of a sharpener is a = $0.95.

7 0

2 years ago

Solve five ninths minus two sixths equals blank.

larisa [96]

Answer:

6/3 I think so try c and if it’s not I’m not sure

Step-by-step explanation:

6 0

2 years ago

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago