Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
2*2*2*3*5*5
or
2^3 *3* 5^2
Step-by-step explanation:
600 = 60*10
These are not prime so keep going, breaking 60 and 10 down
= 6*10 * 5*2
6 and 10 are not prime so keep going ( 5 and 2 are prime)
= 3*2 * 5*2 * 5*2
All of the numbers are prime, so we normally write them in order from smallest to largest
2*2*2*3*5*5
We can write with exponents
2^3 *3* 5^2
Answer: X =5/2, 15/2 x=2.5, 7.5
Step-by-step explanation:
An=-5n+260
A40=60
So the Awnser is 60
(Hope this helped!!)
