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3 years ago

6

A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35

o with respect to the vertical

1 answer:

GenaCL600 [577]3 years ago

7 0

Answer:

F_x = 295.4N

Explanation:

180°-90°-35°= 55°

F= m(a)

F_y = 43kg(9.81m/s²)

F_y = 421.83N

tan(55°) = 421.83N/F_x

F_x = 421.83N/tan(55°)

F_x = 295.3685458N

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3 years ago

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Answer:

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