A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35
o with respect to the vertical
1 answer:
Answer:
F_x = 295.4N
Explanation:
180°-90°-35°= 55°
F= m(a)
F_y = 43kg(9.81m/s²)
F_y = 421.83N
tan(55°) = 421.83N/F_x
F_x = 421.83N/tan(55°)
F_x = 295.3685458N
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