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bearhunter [10]

2 years ago

9

A woman drives a 45 gram golf ball off of a tee and gives the ball a velocity of 28 m/s to the right. What is the change in mome

ntum of the ball?

1 answer:

lidiya [134]2 years ago

7 0

Answer:

1.26

Explanation:

change 45 grams to kilograms which is 0.045 then just multiply it by 28 m/s

0.045x28=1.260

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Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number

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3 years ago

A block oscillating on a spring has period T = 2.8 s . (Note: You do not know values for either m or k. Do not assume any partic

olasank [31]

Answer:

Part a)

T = 3.96 s

Part b)

T = 1.98 s

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T = 2.8 s

Explanation:

As we know that time period of spring block system is given as

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

Part a)

If the mass of the block attached is doubled

then we will have

$T' = 2\pi\sqrt{\frac{2m}{k}}$

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$T' = 3.96 s$

Part b)

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Part c)

If the amplitude is halved but mass and spring constant will remain the same

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so we will have

$T = 2\pi\sqrt{\frac{m}{k}}$

T = 2.8 s

7 0

3 years ago