Answer:
![(b)\ t_1 - t_0](https://tex.z-dn.net/?f=%28b%29%5C%20t_1%20-%20t_0)
![(d)\ t_2 - t_1](https://tex.z-dn.net/?f=%28d%29%5C%20t_2%20-%20t_1)
![(e)\ \frac{t_2 - t_0}{2}](https://tex.z-dn.net/?f=%28e%29%5C%20%20%5Cfrac%7Bt_2%20-%20t_0%7D%7B2%7D)
Explanation:
Given
See attachment for complete question
Required
How long to reach the ground from the maximum height
First, calculate the time of flight (T)
![T =t_2 - t_0](https://tex.z-dn.net/?f=T%20%3Dt_2%20-%20t_0)
The time taken (t) from maximum height to the ground is:
![t = \frac{1}{2}T](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B1%7D%7B2%7DT)
So, we have:
![t = \frac{t_2 - t_0}{2}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bt_2%20-%20t_0%7D%7B2%7D)
Another representation is:
At ymax, the time is: t1
On the ground, the time is t2
The difference between these times is the time taken.
So;
![t = t_2 - t_1](https://tex.z-dn.net/?f=t%20%3D%20t_2%20-%20t_1)
Since air resistance is to be ignored, then
--- i.e. time to reach the maximum height from the ground equals time to reach the ground from the maximum height
Answer:
![\boxed {\boxed {\sf v_i= 4 \ m/s}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20v_i%3D%204%20%5C%20m%2Fs%7D%7D)
Explanation:
We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.
![v_f= v_i + at](https://tex.z-dn.net/?f=v_f%3D%20v_i%20%2B%20at)
The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.
= 16 m/s - a= 1.2 m/s²
- t= 10 s
Substitute the values into the formula.
![16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%20%281.2%20%5C%20m%2Fs%5E2%29%2810%20%5C%20s%29)
Multiply.
![16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%20%281.2%20%5C%20m%2Fs%5E2%20%2A%2010%20%5C%20s%29)
![16 \ m/s = v_i + 12 \ m/s](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%2012%20%5C%20m%2Fs)
We are solving for the initial velocity, so we must isolate the variable
. Subtract 12 meters per second from both sides of the equation.
![16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20-%2012%20%5C%20m%2Fs%20%3D%20v_i%20%2B%2012%20%5C%20m%2Fs%20-12%20%5C%20m%2Fs)
![4 \ m/s = v_i](https://tex.z-dn.net/?f=4%20%5C%20m%2Fs%20%3D%20v_i)
The cyclist's initial velocity is <u>4 meters per second.</u>
'G' = "giga..." = billion = 10⁹
'ms' = "millisecond" = 0.001 second
100 Gw = 10¹¹ watts
35 ms = 0.035 second
100 Gw x 35 ms = 10¹¹ watts x 0.035 second = 3.5 x 10⁹ J
= 3.5 G-joules
The correct answer is a I hope that helped enjoy the rest of your weekend
The correct answer is C. amplitude.
Have an awesome day!