Water can only dissolve inorganic compounds is false
Answer:
Empirical formula = C₃S₂
Explanation:
Given data:
Mass of carbon = 44.0 mg (44/1000 = 0.044 g)
Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)
Empirical formula = ?
Solution:
First of all we will calculate the number of moles.
Number of moles of carbon = mass / molar mass
Number of moles of carbon = 0.044 g/ 12.01 g/mol
Number of moles of carbon = 0.0037 mol
Number of moles of sulfur:
Number of moles = mass / molar mass
Number of moles = 0.078 g/ 32,066 g/mol
Number of moles = 0.0024 mol
Now we will compare the moles:
C : S
0.0037/0.0024 : 0.0024/0.0024
1.5 : 1
C : S = 2(1.5 : 1)
C : S = 3 : 2
Empirical formula = C₃S₂
Answer:
If the hydrated salt is overheated, it causes the anhydrous salt to decompose, causing the product to be lost as gas. The reported percentage of water loss will be too high because the gap between the initial measurement and final (which will be lower due to loss of sample) measurement will widen.
Let's break this down. We know from our balanced equation that (in theory) we'll get the same number of moles of copper out of the reaction that we put into it. So we need to find the number of moles of CuSO4 we have in 200.0 grams. Using the molar mass of CuSO4:
200.0 grams CuSO4 * (1 mole CuSO4)/(159.61 grams CuSO4) =
1.253 moles CuSO4
We know that the moles of CuSO4 and Cu are one-to-one, so we should yield the same number of moles of copper. If we multiply by copper's molar mass, we get:
1.253 moles Cu * (63.55 grams Cu)/(1 mole Cu) = 79.63 grams Cu
Answer:
Explanation:
Balanced forces are opposite in direction and equal in size.
Balanced forces are in a state of equilibrium.
