The statement in option B is not correct. B is the correct answer. This is because nuclear fission usually occur in large unstable isotopes, which are bombarded with high speed particles like neutrons, which make them to split into smaller particles. The statement in option A, C and D are true about nuclear fission.
The answer is b, because the earth produced all of it,
Answer : Option 3) Tin and Silver.
Explanation : The elements which will be malleable (thin sheets) and good conductors of electricity has to be a metal.
i) Iodine and Silver - Iodine is a non-metal and is crystalline in nature so, it cannot be malleable. Although silver is a malleable element and is a good conductor of electricity, but the combination cannot be right. Also iodine is bad conductor of electricity.
ii) Iodine and xenon - Iodine is non malleable and bad conductor of electricity, whereas xenon is a noble gas which cannot be malleable but is a good conductor of electricity.
iii) Tin and Silver- Both are metals in nature and possess the property of being malleable and good conductors of electricity.
iv) Tin and xenon - Tin is although malleable and good conductor of electricity xenon is a gas which is good conductor of electricity but cannot be malleable.
Answer:
It will take 0.0205s for 79% of cyclobutane to decompose
Explanation:
Step 1: Data given
Temperature = 1000 °C
Reaction is first order
rate constant = 76*1/s
The initial cyclobutane concentration is 1.63M
How long (in seconds) will it take for 79% of the cyclobutane to decompose?
When 79% decomposes, there will remain 21 %
ln ([A]0 / [A]t) * = k*t
There are four variables in the rate law, so if we know three of them, we can determine the fourth. In this case we know [A]0, [A], and k, and need to find t.
⇒ with [A]0 = the original amount = 100 % =1
⇒ with [A]t = the amount after it's decomposed = 21 % =0.21
⇒ k = the rate constant = 76/s
⇒ t= the time needed = ?
ln (100/21) = 76t
t = 0.0205 s
It will take 0.0205s for 79% of cyclobutane to decompose