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3 years ago

Preston, can you please help!!!!! Or anyone else!!!!

Mathematics

1 answer:

Scilla [17]3 years ago

3 0

Hello!

First you have to find the probability of a pulling a penny

To find this you put the amount of pennies over the amount of coins

There are 12 coins and 5 pennies

This is a 5/12 probability

Next you have to find the probability of then pulling out a quarter

Since you already took out a coin the total amount is now 11

The probability is 4/11

You multiply the two probabilities together to get the probability of them happening one after antoher

5/12 * 4/11 = 5/33

The answer is D)5/33

Hope this helps!

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What is the value of the expression below when x = 5 and y = 2?<br>X + 6y

Vedmedyk [2.9K]

Instead of X put 5 and instead of y put 2
5+6(2)
5+12= 17

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3 years ago

Click on the numbers to enter the answers in the boxes.

djyliett [7]

Answer:

957 - 249 = 708

The number that goes above the 5 is 4

Number above the 7 is 17

Step-by-step explanation:

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3 years ago

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How long does it take for a car traveling at a speed of 50.0 miles per hour to travel 300 feet?

beks73 [17]

We know, Time = distance / speed
t = 0.0568182 / 50 [ 300 Feet = 0.0568182 miles ]
t = 0.001136 * 3600 s
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3 years ago

Help with numbers 40-48

adelina 88 [10]

Answer: -8

Step-by-step explanation:

8 0

3 years ago

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago