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amm1812
3 years ago
15

The partial pressure of carbon dioxide in air varies with the seasons. Would you expect the partial pressure in the Northern Hem

isphere to be higher in the summer or winter
Chemistry
1 answer:
Stels [109]3 years ago
4 0

Answer:

It will be higher in the summer.

Explanation:

Usually, the winter season is more harsh a weather on leaves than summer because it is wet season and thus has less sunlight and this means there will be less photosynthesis reactions and therefore it means the partial pressure will be lesser here unlike in the summer when it is a more warm and dry weather with sunlight where photosynthesis reactions will be more favorable to occur.

Thus, CO2 which is a great component of photosynthesis is used more in the summer and as such the partial pressure in the summer will be higher.

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For each of the following, use the periodic table to determine the number of valence electrons in an atom of the element.
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Explanation:

Ne 8. S 6. Mg 2. Sn 4. C 4. Al 3. Te 6. Cs 1. Bi 5. Br 7. Ga 3. P 5.

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3 years ago
How many grams of hcl can dissolve in 200 g of water at 60 c?
Eddi Din [679]

The solubility curve is a plot of solubility against temperature.

<h3>What is solubility?</h3>

The term solubility refers to the amount of substance that dissolves in solution at a given temperature. Hence, the solubility curve is a plot of solubility against temperature.

Thus, from the solubility curve (not shown) the amount if HCl dissolved can be obtained hence the question is incomplete.

Learn more about solubility:brainly.com/question/8591226

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2 years ago
Some properties, like boiling point elevation and freezing point depression, change in solutions due to the presence and number
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D. quantitative properties

Boiling point and freezing point depression are both values that can be represented quantitatively (in number form).

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3 years ago
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Who was the first to propose the existence of atoms
aleksandrvk [35]
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5 0
3 years ago
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N204(0) + 2NO2(g)
user100 [1]

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

<h3>Further explanation</h3>

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}

Setup 1 :

\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}

Q<K⇒The reaction moved to the right (products)

Setup 2 :

\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}

Q=K⇒the system at equilibrium

Setup 3 :

\tt Q=\dfrac{0.230^2}{0.420}=0.126

Q>K⇒The reaction moved to the left (reactants)

8 0
3 years ago
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