I assume the question asks to expand the expression to individual terms.
There are different ways to approach this, all based on FOIL or similar methods.
I prefer to split it into two parts, as follows:
(x+y+2)(y+1)
=x(y+1)+(y+2)(y+1)
=xy+x+y^2+3y+2
Answer:
x = 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality<u>
</u>
<u>Algebra I</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Identify</u>
<em>a</em> = 12
<em>b</em> = 5
<em>c</em> = x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [PT]: 12² + 5² = x²
- Evaluate exponents: 144 + 25 = x²
- Add: 169 = x²
- [Equality] Square root both sides: ±13 = x
- Rewrite: x = ±13
Since we are dealing with positive numbers, we can disregard the negative root.
∴ x = 13
Answer:
A. Perpendicular
Step-by-step explanation:
When lines and/or points are in perpendicular to one another, the perpendicularity line between them measures the distance between both points and/or lines.
So to measure the distance between point c and line AB, a perpendicular line has to be drawn from c to AB or from AB to c. Either of these will arrive at the same result.
It should also be noted that the angle at the point of intersection of perpendicular lines is 90°.
After simplifying the expression, we get 18a^6b^9
Which tells us choice C is correct.
Have a great day! Let me know if you have more questions.
~Brooke❤️
Answer:
The roots of given quadratic equation lies from 
Step-by-step explanation:
Given as :
The quadratic equation is x² - x -6 = 0
The quadratic equation is in form of ax² + bx +c = 0
Let x1 and x2 be the roots of equation
Sum of roots
So, 
And products of roots is x1 × x2 = 
So, 
Or, x1 + x2 = 1 ......A
And x1 × x2 = 
Or, x1 × x2 = - 6
Now, (x1 - x2)² = (x1 + x2)²+ 4×x1×x2
Or, (x1 - x2)² = (1)²+ 4×6
Or, (x1 - x2)² = 25
So , x1 - x2 = 
= 5 ......B
Now solve eq A and eq B
Or, (x1 + x2) + (x1 - x2) = 1 +5
Or, 2 x1 = 6
∴ x1 = 3 And x2 = - 2
Hence The roots of given quadratic equation lies from Answer
