Answer:
A. (5,-8)
Step-by-step explanation:
Assume your list of points is
A. (5, -8); B. (4, -8); C. (-5, -8); D. (5, 8); E. (4, 5); F. (5, 0)
One way to solve this problem is to insert the values into the expression to see what works
A. (5, -8)

B. (4, -8)

C. (-5, -8)

D. (5, 8)
E. (4, 5)

F. (5, 0)

Only Point A satisfies the equation.
The graph below shows that only Point A is on the line.