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NemiM [27]
3 years ago
14

Which point line on the line describes the equation y+8=4(x-5)

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

A. (5,-8)  

Step-by-step explanation:

Assume your list of points is

A. (5, -8); B. (4, -8); C. (-5, -8); D. (5, 8); E. (4, 5); F. (5, 0)

One way to solve this problem is to insert the values into the expression to see what works

A. (5, -8)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\-8 + 8 & = & 4(5 - 5)\\0 & = & 4(0)\\0 & = & 0\\\end{array}\\\textbf{TRUE}

B. (4, -8)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\-8 + 8 & = & 4(4 - 5)\\0 &=&4(-1)\\0 & = & -4\\\end{array}\\\textbf{False}

C. (-5, -8)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\-8 + 8 & = & 4(-5 - 5)\\0& = & 4(-10)\\0 & = & -40\\\end{array}\\\textbf{False}

D. (5, 8)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\8 + 8 & = & 4(5 - 5)\\16 & = & 4(0)\\16 & = & 0\\\end{array}\\\textbf{False}

E. (4, 5)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\5 + 8 & = & 4(4 - 5)\\13 & = & 4(-1)\\13 & = & -4\\\end{array}\\\textbf{False}

F. (5, 0)

\begin{array}{rcl}y + 8 & = & 4(x - 5)\\0 + 8 & = & 4(5 - 5)\\8 & = & 4(0)\\8 & = & 0\\\end{array}\\\textbf{False}

Only Point A satisfies the equation.

The graph below shows that only Point A is on the line.

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