How many electrons will aluminum gain or lose when it forms an ion?

Fittoniya [83]

For distance vs time graphs, the slope stands for speed, as speed is a scalar, along with distance.
For displacement (position) vs time graphs, the slope stands for velocity, as velocity is a vector, along with displacement.

7 0

3 years ago

Tether ball is a game children play in which a ball hangs from a rope attached to the top of a tall pole. The children hit the b

Murljashka [212]

Answer:

a_total = 14.022 m/s²

Explanation:

The total acceleration of a uniform circular motion is given by the following formula:

$a=\sqrt{a_c^2+a_T^2}$ (1)

ac: centripetal acceleration

aT: tangential acceleration

Then, you first calculate the centripetal acceleration by using the following formula:

$a_c=r\omega^2$

r: radius of the circular trajectory = 2.0m

w: final angular velocity of the ball = 7.0 rad/s

$a_c=(2.0m)(7.0rad/s)^2=14.0\frac{m}{s^2}$

Next, you calculate the tangential acceleration. aT is calculate by using:

$a_T=r\alpha$ (2)

α: angular acceleration

The angular acceleration is:

$\alpha=\frac{\omega_o-\omega}{t}$

wo: initial angular velocity = 13 rad/s

t: time = 15 s

Then, you use the expression for the angular acceleration in the equation (1) and solve for aT:

$a_T=r(\frac{\omega_o-\omega}{t})=(2.0m)(\frac{7.0rad/s-13.0rad/s}{15s})=-0.8\frac{m}{s^2}$

Finally, you replace the values of aT and ac in the equation (1), in order to calculate the total acceleration:

$a=\sqrt{(14.0m/s^2)^2+(-0.8m/^2)^2}=14.022\frac{m}{s^2}$

The total acceleration of the ball is 14.022 m/s²

5 0

4 years ago

A sandbag motionless in outer space is hit by a three-times-as massive sandbag moving at 12 m/s. They stick together. This is an

vekshin1

Answer:

This is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

Explanation:

Let the mass of the motionless sandbag = m₁

Let the mass of the moving sandbag = m₂ = 3m₁

initial velocity of the motionless sandbag, u₁ = 0

initial velocity of the moving sandbag, u₂ = 12 m/s

Let their final velocity, = v

Collision between two particles can either be elastic or inelastic.

Since they stick together after the impact, then the collision is inelastic

Apply the principle of conservation of linear momentum;

Initial kinetic energy = final kinetic energy

¹/₂m₁u₁² + ¹/₂m₂u₂² = ¹/₂v²(m₁ + m₂)

¹/₂m₁(0)² + ¹/₂(3m₁)(12)² = ¹/₂v²(m₁+3m₁)

216m₁ = 2m₁ v²

v² = 108

v = √108

v = 10.392 m/s

Change in kinetic energy = Final kinetic energy - initial kinetic energy

Initial Kinetic energy, KE₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

KE₁ = ¹/₂m₁(0)² + ¹/₂(3m₁)(12)²

KE₁ = 216m₁ J

Final kinetic energy, KE₂ = ¹/₂v²(m₁ + m₂)

KE₂ = ¹/₂(108)(m₁ + 3m₁)

KE₂ = 216m₁ J

ΔKE = KE₂ - KE₁ = 216m₁ J - 216m₁ J = 0%

Therefore, this is an example of inelastic collision and it loses zero(0) % of initial kinetic energy

4 0

3 years ago

Can friction ever<br> do positive work?

PtichkaEL [24]

Answer:

say whaaaaaaaat?

Explanation:

hell tho

7 0

3 years ago

True or false Carbon in the form of carbon dioxide is needed for both processes of photosynthesis and cellular respiration True

Anna007 [38]

Yes carbon dioxide is needed for photosynthesis while cellular respiration needs oxygen and dispurses carbon dioxide

5 0

3 years ago