Answer:
7 m/s^2
Explanation:
Given that the jet is traveling 37.6 m/s when the pilot receives the message.
And it takes the pilot 5.37 s to bring the plane to a halt.
Acceleration of the plane can be calculated by using first equation of motion
V = U - at
Since the plane is going to stop, the final velocity V = zero.
And the acceleration will be negative
Substitute all the parameters into the formula
0 = 37.6 - 5.37a
5.37a = 37.6
Make a the subject of formula
a = 37.6 / 5.37
a = 7.0 m/s^2
Therefore, the acceleration of the plane to bring the plane to a halt is 7 m/s^2
Dependent on what you are measuring and what took you are using. Please be more specific.
Solve the equation.it is hard to see
Answer:
this is a no brainer
Explanation:
As air pressure in an area increases, the density of the gas particles in that area increases.
Use the definition of acceleration:
Acceleration = (change of velocity) divided by (time for the change)
The graph says:
Change of velocity = -6 m/s
Time for the change = 3 sec
So Acceleration = (-6m/s) / (3 s)
That's -6/3 m/s•s
or
-2 m/s^2
