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Jobisdone [24]
3 years ago
15

How many electrons will aluminum gain or lose when it forms an ion?

Physics
1 answer:
Tanya [424]3 years ago
6 0
In the form of an ion, Al 3+, It will lose 3 electrons
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Which reasons explain why a theory would be changed or replaced?
icang [17]

Answer:

It would be changed or replaced when new information is presented that proves the theory needs to be reconstructed

Explanation:

6 0
4 years ago
Two isolated copper plates, each of area 0.40 m2, carry opposite charges of magnitude 7.08 × 10-10 C. They are placed opposite e
polet [3.4K]

Answer:

The potential difference between the plates is 8 V.

Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

We need to calculate the electric field

Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

Where, q = charge

A = area

Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

E=200\ V/m

We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

d = distance

Put the value into the formula

V=200\times0.04

V=8\ V

Hence, The potential difference between the plates is 8 V.

3 0
4 years ago
Create a model in the space below that demonstrates how action potentials ensue. A sample model can be found under the Unit Pack
Pepsi [2]

Answer:

K+NA+30

Explanation:

8 0
3 years ago
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
3 years ago
Mrs. Stark weighs 70kg. How much Potential Energy does she have if she stands on the roof of an 80m tall building?
sesenic [268]

70kg

1 earth gravity

80 M of height

---------------------------------

54917.2 Joules of energy

Mrs. Stark has 54,917.2 Joules of energy.

3 0
3 years ago
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