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zmey [24]
3 years ago
8

Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has

a wavelength of 784 m?
Physics
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

Explanation:

Given

Wavelength of radiation \lambda =784\ m

We know Energy of wave with wavelength \lambda is given by

E=\frac{hc}{\lambda }

where h=Planck's constant

c=velocity of light

\lambda=wavelength of wave

E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}

E=2.53\times 10^{-28}\ J

Hence the energy of the wave with wavelength 784 m is 2.53\times 10^{-28}\ J

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35.6 m

Explanation:

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3 years ago
A sample of an ideal gas has a volume of 2.37 L at 2.80×102 K and 1.15 atm. Calculate the pressure when the volume is 1.68 L and
iogann1982 [59]

Answer:

p_2 = 1.76 atm

Explanation:

given data:

v_1 = 2.37 L

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t_1 = 280 K

t_2 = 304 K

from Gas Law Equation

, WE HAVE

\frac{p_1 v_1}{t_1} =\frac{p_2 v_2}{t_2}

Putting the values

\frac{1.15*2.37}{280}  =\frac{p_2 *1.68}{304}

9.733*10^{-3} = \frac{p_2 *1.68}{304}

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\frac{9.733*10^{-3}*304}{1.68} =p_2

p_2= 1.76 atm

7 0
3 years ago
Two spacecraft are both 10 million kilometers from a star. The total power output of the star is 4 x 1025 W. Spacecraft 1 has a
Ksenya-84 [330]

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For both panels we would have to

\frac{\text{Power by panel 1}}{\text{Power by panel 2}} = \frac{r_1^2}{r_2^2}

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Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
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Answer:

v = 2.18m/s

Explanation:

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