PLEASE HELP WILL MARK BRAINLEIST

Please help URGENT! WILL GIVE BRAINLEST AND 30 POINTS

ivanzaharov [21]

Answer:

The answer you are looking for is the letter B on your assignment hun. Merry almost Christmas☃️

5 0

2 years ago

Read 2 more answers

PLEASE HELP EASY MATH!!!!

Snowcat [4.5K]

D 20 cubic feet would be your answer

8 0

3 years ago

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Can you find the limits of this

Pavel [41]

Answer:

$\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{-3}{8}$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Constant]: $\displaystyle \lim_{x \to c} b = b$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

L'Hopital's Rule

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

We are given the following limit:

$\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16}$

Let's substitute in x = -2 using the limit rule:

$\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{(-2)^3 + 8}{(-2)^4 - 16}$

Evaluating this, we arrive at an indeterminate form:

$\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \frac{0}{0}$

Since we have an indeterminate form, let's use L'Hopital's Rule. Differentiate both the numerator and denominator respectively:

$\displaystyle \lim_{x \to -2} \frac{x^3 + 8}{x^4 - 16} = \lim_{x \to -2} \frac{3x^2}{4x^3}$

Substitute in x = -2 using the limit rule:

$\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{3(-2)^2}{4(-2)^3}$

Evaluating this, we get:

$\displaystyle \lim_{x \to -2} \frac{3x^2}{4x^3} = \frac{-3}{8}$

And we have our answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

6 0

2 years ago

40 POINTS- Are a logistic equation and a logistic regression model the same thing? If not, what's the difference?

pychu [463]

Answer: They are diffrent

Step-by-step explanation: The logistic equation was first published by Pierre Verhulst in 1845. This differential equation can be coupled with the initial condition P(0) = P0 to form an initial-value problem for P(t). Suppose that the initial population is small relative to the carrying capacity. Then P K is small, possibly close to zero.

The logistic regression coefficients are the coefficients b 0, b 1, b 2,... b k of the regression equation: An independent variable with a regression coefficient not significantly different from 0 (P>0.05) can be removed from the regression model (press function key F7 to repeat the logistic regression procedure).

By the way, this is copied from the internet.

8 0

2 years ago

which of the following values would complete the ordered pair if the point is on the graph f(x)=-2x+3 (-1,___)

Mars2501 [29]

I believe the awnser would be 5. what you have to do is you plug in the -1 where the x is, remember that the 2 is a negative so that would make it a positive 2. I'm not sure if your teacher taught you this but my teacher taught us that f(x)=Mx+b is just another version of y=Mx+b.

4 0

3 years ago