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Natali5045456 [20]
3 years ago
14

Chlorine gas reacts with solid phosphorus to form phosphorus trichloride gas. Write a balanced chemical equation for this reacti

on.​
Chemistry
1 answer:
Oduvanchick [21]3 years ago
7 0

Explanation:

First write down the basic chemical equation with the reactants and products,

\text{P}_4+\text{ Cl}_2\to\text{ PCl}_3

Balancing the chemical equation*,

\text{P}_4 (s) + 6 \text{Cl}_2 (g) \to 4 \text{PCl}_3 (l)

\color{blue}\text{Note: To balance any chemical equations, we should ensure the number of atoms of each elements are the same on both the product and reactant side.}

\color{blue}\text{The phosphorous molecule has 4 P, but the }\text{PCl}_3\text{ molecule on the product side only has one P atom. Therefore, we need 4 }\text{PCl}_3\text{ molecules to balance.}

\color{blue}\text{But that will mean we have }4\cdot 3=12\text{Cl atoms on the product side. So we need 6 }\text{Cl}_2 \text{ molecules on the reactant side.}

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a solution is prepared by dissolving 55g of CaCl2 into 300g of water. if the Kf of water is -1.86 c/m, shat is the freezing poin
Zepler [3.9K]

Answer:

Relation between , molality and temperature is as follows.

                T =

It is also known as depression between freezing point where, i is the Van't Hoff factor.

Let us assume that there is 100% dissociation. Hence, the value of i for these given species will be as follows.

         i for  = 3

          i for glucose = 1

          i for NaCl = 2

Depression in freezing point will have a negative sign. Therefore, d

depression in freezing point for the given species is as follows.

       

                 =

       

                  =

     

                   =

Therefore, we can conclude that given species are arranged according to their freezing point depression with the least depression first as follows.

                    Glucose < NaCl <

Explanation:

3 0
3 years ago
Question 7 of 15
Crazy boy [7]

Answer: 0.4 moles

Explanation:

Given that:

Volume of gas V = 11L

(since 1 liter = 1dm3

11L = 11dm3)

Temperature T = 25°C

Convert Celsius to Kelvin

(25°C + 273 = 298K)

Pressure P = 0.868 atm

Number of moles N = ?

Note that Molar gas constant R is a constant with a value of 0.00821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.868atm x 11dm3 = n x (0.00821 atm dm3 K-1 mol-1 x 298K)

9.548 atm dm3 = n x 24.47atm dm3mol-1

n = (9.548 atm dm3 / 24.47atm dm3 mol-1)

n = 0.4 moles

Thus, there are 0.4 moles of the gas.

3 0
3 years ago
A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem
BartSMP [9]

Answer:

Q_{metal} = -6799\,J

Explanation:

By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:

Q_{metal} = - Q_{w}

Q_{metal} = m_{w} \cdot c_{p,w}\cdot (T_{1}-T_{2})

Q_{metal} = (250\,g)\cdot \left(4.184\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (25\,^{\textdegree}C - 31.5\,^{\textdegree}C)

Q_{metal} = -6799\,J

6 0
3 years ago
Read 2 more answers
Are these answers correct? I’m a little unsure
Naily [24]

Answer:

yes I think that they are correct

8 0
3 years ago
A hydrocarbon sample was burned in a bomb calorimeter. The temperature of the calorimeter and the 1.00 kg of water rose from 20.
fomenos

Answer:

The heat released by the combustion is 20,47 kJ

Explanation:

Bomb calorimeter is an instrument used to measure the heat of a reaction. The formula is:

Q = C×m×ΔT + Cc×ΔT

Where:

Q is the heat released

C is specific heat of water (4,186kJ/kg°C)

m is mass of water (1,00kg)

ΔT is temperature change (23,65°C - 20,45°C)

And Cc is heat capacity of the calorimeter (2,21kJ/°C)

Replacing these values the heat released by the combustion is:

<em>Q = 20,47 kJ</em>

6 0
3 years ago
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