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Verizon [17]
2 years ago
15

V/5−6=3 please show how you got it thx

Mathematics
2 answers:
posledela2 years ago
8 0
The answer is v=45!
Gennadij [26K]2 years ago
5 0
This is the way I got it the answer is v= 45

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3. Which statement below is the conclusion
Marrrta [24]

Answer:

a number hahah

Step-by-step explanation:

as i guess i think haha

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2 years ago
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A^4 + 2b OVER a; if a =3 and b = 12
Tems11 [23]

Answer:

105

Step-by-step explanation:

Given : a = 3, b = 12

3 ⁴ = 81

2 x 12 = 24

Result:

81 + 24

= 105

6 0
2 years ago
Simplify the following expression: (−3)(−2)( −2)<br> A −12<br> B 12<br> C −18<br> D 18
nydimaria [60]
A -12 Hope this helps
7 0
3 years ago
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A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
A farmer plans to fence a rectangular pasture adjacent to a river the pasture must contain 405,000 square meters
jeyben [28]

The dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

Let's suppose x and y are the sides of the rectangular garden and y is the parallel to the river.

Then according to the problem:

2x + y = P ..(1)

P is the perimeter of the rectangle.

xy = 405000  (area of the rectangle)

Plug the value of y in the equation (1) from the above equation.

P(x) = 2x + 405000/x

P'(x) = x—405000/x² = 0

x = 450 m

P''(x) > 0 hence at x = 450 the value of P(x) is minimum.

y = 405000/450

y = 900 m

P(min) = 1800 m

Thus, the dimensions of the garden that will require the least amount of fencing are 450 m and 900 m and the perimeter of the area is 1800 m.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ4

7 0
2 years ago
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