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nydimaria [60]
3 years ago
6

You do no know an objects velocity until you know its _____.

Physics
1 answer:
Triss [41]3 years ago
4 0
I agree with the answer above, but since velocity is a vector, I think displacement would be a better answer :)
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A car takes 10 minutes to travel 10 km calculate average speed of car.​
lisabon 2012 [21]

Answer:

(km/mins) × ( mins/hr) = km/hr

(10/10)×(60/1) =600/10 = 60 km /hr

......

5 0
3 years ago
A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?
kolbaska11 [484]
The correct answer is: 1792g or 1800g.

(When you round it)
8 0
4 years ago
A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220
disa [49]
First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force, \mu m g. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
ma=-\mu m g
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2

Now we can use the following relationship to find the distance covered by the skier before stopping, S:
2aS=v_f^2-v_i^2
where v_f=0 is the final speed of the skier and v_i=4.75 m/s is the initial speed. Substituting numbers, we find:
S=- \frac{v_i^2}{2a}=- \frac{(4.75 m/s)^2}{2(-2.16 m/s^2)}=5.23 m
5 0
3 years ago
How can you use a magnet to induce a current?
Furkat [3]
A coil of wire with a current flowing thru it becomes a magnet
3 0
4 years ago
Read 2 more answers
If the PLATE SEPARATION of an isolated charged parallel-plate capacitor is doubled: A. the electric field is doubled
mash [69]

Explanation:

The electric field of an isolated charged parallel-plate capacitor is given by :

E=\dfrac{q}{A\epsilon_o}........(1)

Where

q is the electric charge

A is the area of cross section of parallel plate

It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.

So, the correct option is (E) i.e. "none of the above".

5 0
3 years ago
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