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3 years ago

You do no know an objects velocity until you know its _____.

Physics

1 answer:

Triss [41]3 years ago

4 0

I agree with the answer above, but since velocity is a vector, I think displacement would be a better answer :)

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the physical phenomenon produced by moving electric charge

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3 years ago

A car travels 60 miles in the first 2 hours and 68 miles in the next 2 hours

Gemiola [76]

32miles/hr

Explanation:

Given parameters:

Distance 1 = 60miles

Time 1 = 2hrs

Distance 2 = 68miles

Time 2 = 2hrs

Unknown:

Average speed of the car = ?

Solution:

Average speed is the total distance covered in a particular duration of time.

Average speed = $\frac{total distance}{total time taken}$

Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs

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Average speed = $\frac{128miles}{4hrs}$ = 32miles/hr

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4 years ago

What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

Paul [167]

Answer:

$\Delta P=1581357.92\ Pa$

Explanation:

Given:

diameter of hose pipe, $D=0.09\ m$

diameter of nozzle, $d=0.03\ m$

volume flow rate, $\dot{V}=40\ L.s^{-1}=0.04\ m^3.s^{-1}$

Now, flow velocity in hose:

$v_h=\frac{\dot V}{\pi.D^2\div 4}$

$v_h=\frac{0.04\times 4}{\pi\times 0.09^2}$

$v_h=6.2876\ m.s^{-1}$

Now, flow velocity in nozzle:

$v_n=\frac{\dot V}{\pi.d^2\div 4}$

$v_n=\frac{0.04\times 4}{\pi\times 0.03^2}$

$v_n=56.5884\ m.s^{-1}$

We know the Bernoulli's equation:

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2$

when the two points are at same height then the eq. becomes

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}$

$\Delta P=\frac{\rho(v_n^2-v_h^2)}{2}$

$\Delta P=\frac{1000(56.5884^2-6.2876^2)}{2}$

$\Delta P=1581357.92\ Pa$

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3 years ago

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