Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Circle graphs or pie charts are used to represent data in percentages or proportions
- 192 voted for Goron
- 288 voted for Smith or Fishman
<h3>People that voted for Goron</h3>
The total number of votes is given as:
Total = 640
The circle chart is not given.
So, we make use of an assumed value
Assume 30% voted for Goron
The number of people would be:
Goron = 30% * 640
Evaluate
Goron = 192
Hence, 192 voted for Goron using the assumed value
<h3>People that voted for Smith or Fishman</h3>
Assume 45% voted for Smith or Fishman
The number of people would be:
Smith or Fishman = 45% * 640
Evaluate
Smith or Fishman = 288
Hence, 288 voted for Smith or Fishman using the assumed value
Read more about circle graphs at:
brainly.com/question/24461724
So a diameter is twice the radius
The formula is:
V = π(r^2)(h/3)
the half of 300 is 150, so the radius is 150
V = π(150^2)(150/3)
V = π(22500)(50)
V is about <span>3534291.74</span>
Okay, we start with 42x^2 + 32 - 18 = 6062. To solve single-variable equations like this one, we want to isolate the x by moving all of the other numbers to the other side of the equation. We need to first subtract 32 and 18, and that equals 14. Now our problem looks like this, 42x^2 + 14 = 6062. Since 14 is the only other number on the left side, we subtract four from both sides! This gives us 42x^2 + 14 - 14 = 6062 - 14, so 42x^2 = 6062. Now to find x, we want to just have one x on the left side instead of 42, so we divide the equation by 42 to find that 42x^2/42 = 6048/42, so x = 12
