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snow_tiger [21]
2 years ago
12

Its the last one:) please help. giving brainlist

Mathematics
2 answers:
diamong [38]2 years ago
5 0

Answer:

5

Step-by-step explanation:

Segments are named by their endpoints. Therefore, segment PQ will have endpoints P and Q. The length of the segment is equal to the distance between these points.

To find the distance between P and Q given their coordinates, use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let:

P(-2, 7)\implies (x_1, y_1),\\Q(1, 3)\implies (x_2, y_2)

The distance between these points is equal to:

d=\sqrt{(1-(-2))^2+(3-7)^2},\\d=\sqrt{3^2+(-4)^2},\\d=\sqrt{9+16},\\d=\sqrt{25},\\d=\boxed{5}

Leto [7]2 years ago
5 0

Answer:

5

Step-by-step explanation:

This problem gives one the following points on a line: (P(-2,7)), and (Q(1,3)). The problem asks one to find the distance between the two points. The formula to find the distance between two points on a coordinate point is the following,

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the given values in and solve for the distance;

D=\sqrt{(-2)-(1))^2+((7)-(3))^2}

Simplify,

D=\sqrt{(-2)-(1))^2+((7)-(3))^2}\\\\D=\sqrt{(-3)^2+(4)^2}\\\\D=\sqrt{9+16}\\\\D=\sqrt{25}\\\\D = 5

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5 0
2 years ago
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PLZ I'M BEING TIMED Which equation could have been used to create this table?
Talja [164]

Answer:

y=6x

Step-by-step explanation:

Let us assume the table is the one shown in the attachment.

We can observe the following pattern from the table:

12=6*2

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y=6*x

Therefore the equation that could have been used to create this table is

y=6x

7 0
2 years ago
Solve the equation for x.
ivann1987 [24]

Answer:

x = 44

Step-by-step explanation:

sqrt(x+5) -3 =4

Add 3 to each side

sqrt(x+5) -3+3 =4+3

sqrt(x+5)  =7

Square each side

(sqrt(x+5))^2  =7^2

x+5 = 49

Subtract 5 from each side

x+5-5 = 49-5

x=44

3 0
3 years ago
Read 2 more answers
O GRAPHS, FUNCTIONS, AND SEQUENCES
WINSTONCH [101]
Always use the formula (y2-y1)/(x2-x1) to find a line’s slope, given two points:

(-1- -8)/(4-5) = 7/-1 = -7

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7 0
2 years ago
The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0
3 years ago
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